This is somewhat misleading, and I encountered the same question in my homework. An electric field strength of 1*10^5 N/C is provided, along with a drag force of 7.25*10^-11 N, and the critical detail is that it maintains a constant velocity, indicating that the particle is in equilibrium and not accelerating.
<span>To solve, utilize F=(K*Q1*Q2)/r^2 </span>
<span>You'll want to equate F with the drag force, where the electric field strength translates to (K*Q2)/r^2; substituting the values results in </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
Answer:
All three pendulums will have the same angular frequencies.
Explanation:
For a simple pendulum, the time period using the approximation
is expressed as:

The angular frequency
is defined as

Since the angular frequency remains unaffected by the initial angle (valid strictly for small angle approximations), we deduce that the angular frequencies of the three pendulums are identical.
Answer:
0.6
Explanation:
The formula for the volume of a sphere is 
Thus 
The radius of the disk is 
Applying angular momentum conservation;
The
of the sphere = 
of the disk = 

= 0.6
Answer:
Explanation:
For a 60W light bulb used for 1 minute:
P = 60 W
t = 1 minute = 60 seconds
This energy is capable of lifting an object weighing 10N.
W = 10N
This indicates conversion of electrical energy into potential energy.
Let's calculate the electrical energy:
Power describes the rate of work done.
Power = Work / time
Thus, work = power × time
Work = 60 × 60
Work = 3600 J
Potential energy calculation:
P.E = mgh
Where the weight is given by:
W = mg
Therefore, P.E = W·h
P.E = 10·h
Thus, we equate:
Potential energy = Electrical energy
P.E = Work
10·h = 3600
Dividing both sides by 10 gives:
h = 3600 / 10
h = 360m
The object can be lifted to a height of 360m.