answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alika
1 month ago
7

Be sure to answer all parts. Calculate ΔH o for the following reaction in two ways, using the data given below. H2(g) + I2(g) →

2HI(g) (a) Using the equation ΔH o rxn = ∑(BE(reactants)) − ∑(BE(products)) kJ/mol (b) Using the equation ΔH o rxn = ∑(nΔH o f (products)) − ∑(mΔH o f (reactants)) kJ/mol Bond BE kJ/mol Substance ΔH o f kJ/mol H―H 436.4 H2(g) 0 I―I 151 I2(g) 61.0 H―I 298.3 HI(g) 25.9
Chemistry
1 answer:
alisha [2.9K]1 month ago
7 0
a) ΔH°rxn = -9.2kJ/mol b) ΔH°rxn = -9.2kJ/mol Explanation: By applying Hess's law, the reaction enthalpy ΔH can be calculated from the enthalpies of formation of the reactants and products involved, thus: ΔH°rxn = ∑(BE(reactants)) − ∑(BE(products)). Alternatively, it can be expressed as: ΔH°rxn = ∑(nΔH°f (products)) − ∑(mΔH°f (reactants)). For the given reaction: H₂(g) + I₂(g) → 2HI(g) a) Using the first equation, we find: ΔH°rxn = ΔH (H-H) + ΔH (I-I) - 2ΔHBE (H-I) = 436.4kJ + 151kJ - 2×298.3kJ. After the calculation, ΔH°rxn is determined to be -9.2kJ/mol. b) Based on the second equation: ΔH°rxn = 2ΔH°f (HI) − ΔH°f (H₂) - ΔH°f (I₂). Substituting the values yields ΔH°rxn = 2×25.9kJ - 0kJ - 61.0kJ. This also results in ΔH°rxn = -9.2kJ/mol.
You might be interested in
How much maleic anhydride would you need to react 178 mg of anthracene? Assume 1:1 ratio from maleic anhydride to anthracene.
lions [2927]

Answer:

(1) 0.10 (2) 17.8 g

Explanation:

Since the reaction ratio is 1:1, you will need to convert the provided masses into moles to get the results:

MW of anthracene = 178.23 g/mol

MW of maleic anhydride = 98.06 g/mol

a) mass of anthracene = 178 mg x 1 g/ 1000 mg = 0.178 g of anthracene

Moles of anthracene = 0.178 g of anthracene/ 178.23 g/mol

= 0.001 mol anthracene

0.001 mol anthracene x 1 mol of maleic acid/mol of anthracene

= 0.001 mol of maleic anhydride

mass of maleic anhydride = 0.001 mol x 98.06 g/mol = 0.10 g

b) moles of maleic anhydride = 9.8 g/ 98.06 g/mol = 0.099 moles

0.099 moles of maleic anhydride x 1 mol of anthracene/mol of maleic anhydride =

0.099 mol of anthracene

g of anthracene = 0.10 mol x 178 g/mol = 17.8 g

8 0
1 month ago
Suppose you have a bucket of sand containing 5.5 billion grains of sand ( 5.5×109 grains). Most of the grains of sand are white,
alisha [2963]

Explanation:

5.5 billion grains of sand (5.5×10^9 grains)

Assuming the amount of brown sand is 6.0%, how many brown grains are found in the bucket?

Grains of brown sand = Percentage of brown sand * Total sand in the bucket

Calculated brown grains = 0.06 * 5.5×10^9 = 0.33 x 10^9 = 3.3 x 10^8 grains

If the concentration of brown sand is 6.0 ppm, what is the number of brown grains in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppm = 6 / 1,000,000 = 0.000006

Calculated brown grains = 0.000006 * 5.5×10^9 = 3.3 x 10^4 grains

If the concentration of brown sand is 6.0 ppb, how many brown grains exist in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppb = 6 / 1,000,000,000 = 0.000000006

Calculated brown grains = 0.000000006 * 5.5×10^9 = 3.3 x 10^1 = 33 grains

5 0
2 months ago
The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E
Alekssandra [3086]
The first choice might be correct. I'm sincerely sorry if I am mistaken!

FIRST OPTION (A)(1)
3 0
2 months ago
Read 2 more answers
The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the
Alekssandra [3086]

Answer:

Mitochondria are plentiful in mammalian cells, with their proportions varying across different tissues, from less than 1% in white blood cells to as high as 35% in heart muscle cells. It is essential to understand that mitochondria are not static structures but instead form a dynamic network that frequently undergoes processes of fission and fusion. In skeletal muscle, they exist as part of a reticular membrane network. The two subpopulations, subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria, occupy different subcellular regions and exhibit slight differences in their biochemical and functional characteristics tied to their anatomical context. The SS mitochondria are positioned just beneath the sarcolemma, while IMF mitochondria are found closely associated with myofibrils. Their distinct properties likely play a role in their adaptability. SS mitochondria make up about 10-15% of the total mitochondrial volume and are believed to be more adaptable than their IMF counterparts, despite the latter displaying higher levels of protein synthesis, enzyme activity, and respiration (1).

Explanation:

0 0
3 months ago
Read 2 more answers
Other questions:
  • 1. How many atoms of nitrogen are there in 0.50 mol of (NH4)2CO3?
    5·1 answer
  • In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
    5·1 answer
  • Predict what will observe in below mention experiment.
    10·1 answer
  • What is the molarity of potassium ions in a 0.122 M K2CrO4 solution
    12·2 answers
  • A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?
    11·2 answers
  • A careless laboratory technician wants to prepare 200.0 mL of a 0.025 m HCl(aq) solution but uses a volumetric flask of vol- ume
    8·1 answer
  • If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
    12·1 answer
  • What are the properties of gas
    15·2 answers
  • A 20.0-mL sample of lake water was acidified with nitric acid and treated with excess KSCN to form a red complex (KSCN itself is
    14·1 answer
  • A 1.0 mole pure sample of molten tin is dissolved in a 5.0 mole pure sample of molten copper. The solution is set aside to cool
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!