answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GaryK
1 month ago
9

The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde

nly applied to the initially uncharged plates through a 1025 ohm resistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 55 volts?
Physics
1 answer:
Maru [3.3K]1 month ago
5 0

Explanation:

Data provided:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Separation distance d between the plates = 1 mm = 1×10⁻³ m

Battery voltage, or emf = 100 V

Resistance = 1025 ohm

Solution:

In an RC circuit, the voltage across the plates varies with time t. At the outset, the voltage matches that of the battery, V₀ = emf = 100V. However, after a certain time t, both the resistance and capacitance alter this, leading to a final voltage V expressed as

V = V_{0}(1-e^{\frac{-t}{RC} } )\\\frac{V}{V_{0} } = 1-e(^{\frac{-t}{RC} }) \\e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }

Applying the natural logarithm to both sides,

e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} } \\\frac{-t}{RC} = ln(1-\frac{V}{V_{0} } )\\t = -RCln(1 - \frac{V}{V_{0} })

t = -RC ln (1-\frac{V}{V_{0} })        (1)

Next, we can determine the capacitance using the plates' area.

C = ε₀A/d

  = \frac{(8.85*10^{-12))} (20*10^{-4}) }{1*10^{-3} }

  = 18×10⁻¹²F

We can now find the time it takes for the voltage to drop from 100 to 55 V by substituting C, V₀, V, and R values into equation (1)

t = -RC ln (1-\frac{V}{V_{0} })

 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

You might be interested in
Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem. assuming air
Yuliya22 [3333]
U = 0, the initial vertical velocity

Ignoring air resistance, with g set to 9.8 m/s².

The duration, t, required for the pen to reach a vertical speed of 19.62 m/s can be calculated with
19.62 m/s = 0 + (9.8 m/s²)*(t s)
t = 19.62/9.8 = 2.00 s

Result: 2.0 s
8 0
1 month ago
Which of the following are inertial reference frames? A. A car driving at steady speed on a straight and level road. B. A car dr
Softa [3030]
A. A car moving at a constant speed on a flat, straight road. B. A vehicle traveling at a steady speed on a 10-degree incline. An object operates within an inertial reference frame if there is no net force acting upon it. According to Newton's second law, this implies that the object's acceleration also equals zero. Assessing the scenarios yields: A. A car moving at a constant speed on a flat road qualifies as an inertial reference frame, since its velocity and direction remain unchanged; thus, acceleration is zero. B. A car moving steadily up a 10-degree incline still constitutes an inertial reference frame, for similar reasons. C. A car accelerating after departing a stop sign does not represent an inertial frame due to its change in speed. D. A car driving at a steady speed around a curve cannot be considered an inertial reference frame since its direction is changing, resulting in a change in velocity and thus acceleration. Therefore, options A and B are correct.
8 0
1 month ago
Read 2 more answers
The filament of the light bulb is made of tungsten. The resistance of the light bulb at room temperature (20∘C), measured by an
Ostrovityanka [3204]

Explanation:

The formula illustrating the relationship between resistance and temperature is as follows:

R =

R_{o} + \alpha [T_{2} - T_{1}]

where,   R = final resistance

       

= initial resistanceR_{o}

       

= temperature coefficient of resistivity\alpha

       

= final temperature     T_{2}

       

= initial temperatureT_{1}

Given data as follows.

     

T_{1} = (20 + 273) K = 293 K      

      R = 36 ohm,  

= 3 ohmT_{2}

         

= 0.0045R_{o}

Substituting the provided values into the above formula gives us the following.

        R = \alpha

        36 =

R_{o} + \alpha [T_{2} - T_{1}]      

=

3 + 0.0045 \times [T_{2} - 293]

                 = 7626.33 K

T_{2}Thus, it can be concluded that \frac{34.3185}{0.0045}the temperature of the light bulb at 12.0 V is 7626.33 K.

7 0
2 months ago
In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c
Sav [3153]

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

GDP=\pi } \frac{d^{2} }{4}

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

GDP_{b} =\pi \frac{3^{2} }{4}

Conversely, in darkness, the diameter typically enlarges to 7 mm.

GDP_{b} =\pi \frac{7^{2} }{4}

This indicates an increase in light-gathering capacity.

Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}

Thus, the amount of light the eye can capture is 31.4 mm².

3 0
2 months ago
Other questions:
  • Which, if any, of the following statements concerning the work done by a conservative force is NOT true? All of these statements
    8·1 answer
  • Kayla, a fitness trainer, develops an exercise that involves pulling a heavy crate across a rough surface. The exercise involves
    6·1 answer
  • A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electri
    14·2 answers
  • Find the change in volume for a metallic dental filling due to the difference between body temperature (37.0°C) and the temperat
    15·1 answer
  • Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used
    15·1 answer
  • In 1991 four English teenagers built an eletric car that could attain a speed of 30.0m/s. Suppose it takes 8.0s for this car to
    10·2 answers
  • "a very light ideal spring stretches by 21.0 cm when it is used to hang a 135-n object. what is the weight of a piece of electro
    11·2 answers
  • A simple watermelon launcher is designed as a spring with a light platform for the watermelon. When an 8.00 kg watermelon is put
    15·1 answer
  • A 1 mg ball carrying a charge of 2 x 10-8 C hangs from a
    5·1 answer
  • Imagine two people standing at placemark A and placemark E, looking at each other across the fault. Which of the following state
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!