Answer:
The molar concentration of Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.
Explanation:
When creating a calibration curve in spectrophotometric analysis, you apply Lambert-Beer’s law, which indicates that the absorbance of a compound is directly related to its concentration:
A = E*l*C
Where A stands for absorbance, E is the molar absorption coefficient, l is the path length, and C represents the molar concentration
Using the line equation, you find:
y = 4541.6X + 0.0461
Where Y is the absorbance and X refers to the concentration - we will presume the concentration is expressed in molarity-
Given that the absorbance of the unknown is 0.410:
0.410 = 4541.6X + 0.0461
X = 8.01x10⁻⁵M
The molar concentration of Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.
Answer:
a-294
b-3.401×10^-6
c and d - 2.048×10^18
Explanation:
Multiply the RAM for each individual element by its molecular number, e.g., (c-12×14), and then sum to find the molar mass.
b-The molar mass is expressed in grams/mol, hence convert 1 mg to g, which equals 0.001, and divide it by the molar mass.
c/d-1 mole of any substance consists of 6.023×10^23 (ions, molecules, etc.), therefore we need to find the moles here as
(3.401×10^-6) × (6.023×10^23).
Answer: The molecular formula will be 
Explanation:
When percentages are provided, we assume the total mass to be 100 grams.
Thus, the mass of each element corresponds to the specified percentage.
Mass of C= 70.6 g
Mass of H = 5.9 g
Mass of O = 23.5 g
Step 1: convert given masses to moles.
Moles of C =
Moles of H =
Moles of O =
Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.
For C = 
For H =
For O =
The resulting ratio of C: H: O= 4: 4: 1
Hence, the empirical formula obtained is 
The empirical weight is calculated as = 4(12)+4(1)+1(16)= 68g.
The molecular weight = 136 g/mole
Now the molecular formula needs to be obtained.
The molecular formula can be derived as=
A. 1.01 is the accurate result
Because
The formula used is Pv= nRT
P=1 atm
V= 22.4 L
N= x
R= 0.0821
T= 273 K (since it’s standard temperature)
Thus, (1)(22.4)=(x)(0.0821)(273)
X= 1.001
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C
