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Ira Lisetskai
2 months ago
10

Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul

ate the moles in 900. g of hydrogen gas? Set up the math. But DONT DO ANY OF IT. Just leave your answer as a math expression.
Chemistry
2 answers:
Tems11 [2.7K]2 months ago
8 0

Respuesta:

n = \frac{900}{0.090*22.4}

Explicación:

Dado que 1 mol de gas hidrógeno ocupa 22.4 L, se puede calcular la cantidad de moles de hidrógeno (n) a partir del volumen (V):

1 mol ----- 22.4 L

n ------ V

Aplicando una simple regla de tres:

22.4n = V

n = V/22.4

El volumen se encuentra al dividir la masa (m) por la densidad (d)

V = m/d

<pas>

n = \frac{m}{22.4*d}

Se tiene una masa de 900 g y una densidad de 0.090 g/L:

n = \frac{900}{0.090*22.4}

</pas>
Anarel [2.9K]2 months ago
6 0

Answer:

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Explanation:

Assuming all calculations occur at standard pressure and a temperature of -1.72°C :

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Where

n is the number of moles of hydrogen

n is the mass of hydrogen

\rho is the density of hydrogen

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The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

0.8875gCu(NO_{3})_{2}.2.5H_{2}O\times \frac{1molCu(NO_{3})_{2}.2.5H_{2}O}{232.59gCu(NO_{3})_{2}.2.5H_{2}O} \times \frac{1molCu^{2+} }{1molCu(NO_{3})_{2}.2.5H_{2}O} =3.816\times10^{-3} molCu^{2+}

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Researchers stationed at different areas on a mountain and in a tunnel midway through the mountain boiled water at the same time
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