Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul

Question

17 days ago

10

ate the moles in 900. g of hydrogen gas? Set up the math. But DONT DO ANY OF IT. Just leave your answer as a math expression.

2 answers:

Tems11 [846] · Answer 1 · 2026-02-16T14:53:34+03:00

Respuesta:

n = $\frac{900}{0.090*22.4}$

Explicación:

Dado que 1 mol de gas hidrógeno ocupa 22.4 L, se puede calcular la cantidad de moles de hidrógeno (n) a partir del volumen (V):

1 mol ----- 22.4 L

n ------ V

Aplicando una simple regla de tres:

22.4n = V

n = V/22.4

El volumen se encuentra al dividir la masa (m) por la densidad (d)

V = m/d

<pas>

$n = \frac{m}{22.4*d}$

Se tiene una masa de 900 g y una densidad de 0.090 g/L:

n = $\frac{900}{0.090*22.4}$

</pas>

Anarel [852] · Answer 2 · 2026-02-16T14:51:32+03:00

6 0

Answer:

$n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}$

Explanation:

Assuming all calculations occur at standard pressure and a temperature of -1.72°C :

$n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}$

Where

$n$ is the number of moles of hydrogen

$n$ is the mass of hydrogen

$\rho$ is the density of hydrogen