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Olin
4 months ago
13

The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?

Chemistry
1 answer:
Anarel [2.9K]4 months ago
8 0
1 pm equals 10^{-10} cm. Therefore, 230 pm can be converted to 2.3 × 10^{-8} cm. Atoms are spherical in shape, and the volume of a sphere can be calculated using the formula 4/3πr³. Consequently, the atom's volume is calculated as 4/3π(2.3 × 10^{-8})³. Evaluating this gives 4/3 × (3.142 × 12.167 × 10^{-24}), which simplifies to approximately 5.096 × 10^{-23} cm³. Since 1 m³ is equal to 1,000,000 cm³, we find that the volume of the atom is 5.096 × 10^{-29} m³.
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Compute 4.659×104−2.14×104. Round the answer appropriately.
lions [2927]

Answer: 25,200.


Explanation:


1) Starting with: 4.659 × 10⁴ - 2.14 × 10⁴


2) Significant figures need to be considered.


Because the powers are equal (10⁴), the decimal values can be subtracted directly. However, it is essential to first check significant figures and the count of decimal places.


3) The figure 4.659 × 10⁴ has four significant digits (4, 6, 5, and 9), whereas 2.14 × 10⁴ contains three significant digits (2, 1, and 4).


4) When adding or subtracting values with a different number of decimal places, the answer must reflect the same number of decimal places as the number with the least amount of decimal precision.


5) Prior to performing subtraction, it is necessary to round the numbers to the least decimal places. Given that 2.14 has two decimal places and 4.659 has three, round 4.659 to 4.66.


6) Now perform the subtraction 4.66 - 2.14 = 2.52


7) Then multiply by the power of 10: 2.52 × 10⁴ = 25,200. This is the final answer.

5 0
2 months ago
Read 2 more answers
Specific Heat of Water= 4.186 J/g°C
Alekssandra [3086]

The correct answer is C

NOT D

DON'T BE DECEIVED

4 0
3 months ago
Read 2 more answers
The normal boiling point of c2cl3f3 is 47.6°c and its molar enthalpy of vaporization is 27.49 kj/mol. what is the change in entr
eduard [2782]
Based on the equation:

ΔG = ΔH - TΔS = 0

It follows that ΔS = ΔH/T

So, ΔS = n*ΔHVap / Tvap

- where n represents the number of moles calculated as mass/molar mass

For a mass of 24.1 g

and a molar mass of 187.3764 g/mol

substituting gives:

∴ n = 24.1 / 187.3764g/mol

      = 0.129 moles

The molar enthalpy of vaporization, ΔHvap, is 27.49 kJ/mol

The temperature in Kelvin, Tvap = 47.6 + 273 = 320.6 K

After substitution, we compute ΔS, the change in entropy:

∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K

      = 11 J/K
7 0
3 months ago
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