Calculate the molarity of a 10.0% (by mass) aqueous solution of hydrochloric acid.

The question is incomplete,the complete question:

Determine the molality of a 10.0% (by weight) solution of hydrochloric acid in water:

a) 0.274 m

b) 2.74 m

c) 3.05 m

d) 4.33 m

e) the solution's density is necessary for calculations

Answer:

The molality for a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.

Explanation:

The solution is a 10.0% (by weight) hydrochloric acid mix.

This means there are 10 grams of HCl in 100 grams of the solution.

Amount of HCl = 10 g

Total mass of solution = 100 g

Total mass of solution = Mass of solute + Mass of solvent

Mass of solvent (water) = 100 g - 10 g = 90 g

Calculate moles of HCl =

Mass of water converted to kilograms = 0.090 kg

Molality =

<strongTherefore, the molality of a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.