Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:
Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.
Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
Answer: The mole fraction of nitrogen is calculated to be 0.4615.
Explanation: In the mixture of nitrogen () and hydrogen (
), the mole ratio established is 1: 1.5.
At this juncture, we identify that () serves as the limiting reagent.
When 0.4 moles of () are produced, it will require 0.4 moles of (
) along with 3.4 moles of (
).
The total amount of remaining () ends up being 0.6, while the amount of (
) left in the mixture is 0.3 moles.
The mole fraction of () is computed as 0.6 divided by the sum of 0.6, 0.4, and 0.3, resulting in 0.4615.
Answer: The change in enthalpy will be -13.
Explanation:-
Endothermic reactions absorb heat, while exothermic reactions release heat. In the case of an endothermic reaction, the change in enthalpy is represented as positive, whereas for an exothermic reaction, it is negative.
When one mole of A combines with one mole of B to form three moles of C
So the stoichiometric ratio being halved also results in the enthalpy for the reaction being halved.