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Vikentia
1 month ago
11

Given the following equation and heat of reaction: 2 moles of A combine with 2 moles of B to produce 6 moles of C and 26 kJ What

will be the change in enthalpy in kJ of the reaction of 1 mole of A combining with 1 mole of B to produce 3 moles of C? Include the sign but no units.
Chemistry
1 answer:
KiRa [2.9K]1 month ago
8 0

Answer: The change in enthalpy will be -13.

Explanation:-

Endothermic reactions absorb heat, while exothermic reactions release heat. In the case of an endothermic reaction, the change in enthalpy is represented as positive, whereas for an exothermic reaction, it is negative.

\Delta H  \Delta H

2A+2B\rightarrow 6C+26kJWhen one mole of A combines with one mole of B to form three moles of C

2A+2B\rightarrow 6CSo the stoichiometric ratio being halved also results in the enthalpy for the reaction being halved.\DeltaH=-26kJ

Thus, for this reaction:

 

     

A+B\rightarrow 3C+\frac{26}{2}kJ

The resulting change in enthalpy is -13.

A+B\rightarrow 3C\DeltaH=-13kJ

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