Answer:
The runner's deceleration is -23.33 
Given:
Initial speed = 3.5 
Final speed = 0
Time taken = 0.15 s
To determine:
Deceleration of the runner =?
Used Formula:
Using the first equation of motion,
v = u + at
Where, v = final speed
u = initial speed
a = deceleration
t = duration
Solution:
<pusing the="" first="" equation="" of="" motion="">
v = u + at
Where, v = final speed
u = initial speed
a = deceleration
t = duration
0 = 3.5 + a (0.15)
-3.5 = 0.15 (a)
a = 
a = -23.33
The negative sign indicates that this represents deceleration.
Hence, the deceleration of the runner is -23.33
</pusing>
When helium is released from a compressed container, the decompressed atoms expand and rise, causing the rubber balloon to inflate and float along. In this scenario, helium exists in a gaseous state.
Answer:
The energy expected to be released is calculated to be 4182 Joules.
Explanation:
The total mass of coke is 2 kg, which is equivalent to 2000 g
1 calorie per gram corresponds to 4.184 Joules of energy
4.184 J/gC * 2000g results in 8368 J
1 food calorie approximates to 4186 J
By subtracting, we find 8368 - 4186
Hence, the total energy that will be released amounts to 4182 Joules.
<span>Part b) Find your horizontal distance from the window (answer: 1.5 m)
Part c) Calculate the speed of the ball upon catching it (answer: 8.2 m/s)
I'm confused about what "42 degrees below the horizontal" means. Could someone provide guidance on how to approach this?</span>
Answer:
a) 
b) 
c) 
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing 
in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is:
