To determine the mass of the lead piece, we use the following equation: Q(heat) = mC delta T, where Q equals 78.0 j, M is the mass we want to find, C is the specific heat capacity (0.130 j/g/C), and delta T shows the temperature difference, set at 9.0 c. Rearranging the formula to solve for M gives us M = Q / c delta T. By substituting in the values, we conclude that M = 78.0 j / (0.130 j/g/C * 9.0 C), calculating this gives us a mass of 66.7 g of lead.
3,048 minutes. Explanation: 762 divided by 5, then multiply that number by 20.
Answer:
The correct choice is: option A.
Justification:
To address this inquiry, we need to evaluate the total number of electrons each orbital can accommodate.
Orbital Number of electrons
s 2
p 6
d 10
f 14
Provided options:
A. 1s² 2s² 2p⁶ 3s² This configuration is valid as it aligns with the permitted number of electrons in each orbital and follows the correct sequence.
B. 1s² 2s² 2p⁶ 3s² 3d⁴ This configuration is not accurate because
3d⁴ should follow 3p.
C. 1s² 2s² 2d¹⁰ 2p³ This is incorrect since 2d¹⁰ is not a valid orbital.
D. 1s² 2s^s 2p³ 2d¹⁰ This option contains two errors; s as an exponent does not exist, and 2d¹⁰ is also an invalid description.
Answer: Pentane C5H12
Explanation:
The boiling point is defined as the temperature at which a liquid's vapor pressure matches the external pressure, causing the liquid to turn into vapor.
This compound is likely Pentane, represented as C5H12, since its boiling point falls between that of Butane, with the formula C4H10, and Hexane, with the formula C6H14.
Answer:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
Explanation:
For the reaction A + B → C
The expression for the reaction's rate is:
Δ[C]/Δt = k [A] [B]
Utilizing the values for [A], [B], and Δ[C]/Δt, multiply [A] by [B] to acquire a value of X and consider Δ[C]/Δt as Y. The slope derived from this linear regression will yield k.
Therefore, the results you should have are:
y = 3.60x10⁻² X
Thus, the reaction's rate is:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
I hope this assists you!
