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1 month ago

Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl.

Chemistry

2 answers:

lions [2.9K]1 month ago

5 0

The balanced equation is outlined below:

$\boxed{{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}}$

Further Explanation:

A balanced chemical reaction is one where the numbers of atoms of each element are identical on both sides of the equation, which is essential to comply with the Law of conservation of mass.

Displacement reactions:

These are also referred to as replacement or metathesis reactions. They occur when one reactant displaces another, typically involving a more reactive element taking the place of a less reactive one. Both metals and non-metals can engage in these reactions.

An example of a displacement reaction can be described as:

${\text{A}}+{\text{B}}-{\text{C}}\to{\text{A}}-{\text{C}}+{\text{B}}$

Here are two examples:

(a) Copper metal reacting with silver nitrate produces silver and copper nitrate, which is written as:

${\text{Cu}}+{\text{AgN}}{{\text{O}}_3}\to{\text{Ag}}+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}$

(b) Chlorine gas combined with potassium bromide results in potassium chloride and bromine gas, represented as:

${\text{C}}{{\text{l}}_2}+{\text{KBr}}\to{\text{B}}{{\text{r}}_2}+{\text{KCl}}$

The steps to achieve a balanced chemical equation include:

Step 1: Begin by noting the unbalanced equation of the reaction.

The displacement reaction involves sodium acetate $\left({{\text{NaC}}{{\text{H}}_3}{\text{COO}}}\right)$ and hydrochloric acid $\left({{\text{HCl}}}\right)$ , resulting in NaCl and ${\text{C}}{{\text{H}}_3}{\text{COOH}}$ . The state for ${\text{NaC}}{{\text{H}}_3}{\text{COO}}$ , HCl, NaCl, and ${\text{C}}{{\text{H}}_3}{\text{COOH}}$ is aqueous. The equation without balance appears as:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step 2: Write the count of each type of atom on both sides of the chemical equation.

• For the reactant side:

One sodium atom.

Two carbon atoms.

Two oxygen atoms.

Four hydrogen atoms.

One chlorine atom.

• For the product side:

One sodium atom.

Two carbon atoms.

Two oxygen atoms.

Four hydrogen atoms.

One chlorine atom.

Step 3: Start balancing atoms other than carbon, oxygen, and hydrogen by adjusting their numbers on either side as needed.

Sodium and chlorine are already balanced on both sides. The now active equation is:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step 4: Proceed to balance carbon followed by hydrogen, finishing with oxygen.

Now, carbon, hydrogen, and oxygen are also balanced. The effective reaction reads as:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step 5: Verify if the counts of all atoms on both sides match. If they do, the equation has reached balance.

The balanced equation is:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Learn more:

1. Balanced chemical equation:

2. Covalent bonds formed by nitrogen with its unpaired:

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, displacement reaction, NaCl, CH3COOH, CH3COO, NaCH3COO, HCl, atoms, oxygen, carbon, hydrogen, chlorine.

lorasvet [2.7K]1 month ago

4 0

The balanced equation is:

NaCH₃COO + HCl → NaCl + HCH₃COO

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