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Nataliya
1 month ago
10

Define a function pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyram

id with a rectangular base. Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 Relevant geometry equations: Volume

Engineering
1 answer:
pantera1 [299]1 month ago
5 0

Hi, since you haven't mentioned the programming language needed for your code, I will illustrate how to accomplish it using Python, and you can then adapt the approach to any language you prefer.

Answer:

1. def pyramid_volume(base_length, base_width, pyramid_height):

2.     volume = base_length * base_width * pyramid_height / 3

3.     return volume

Step-by-step explanation:

  1. The function pyramid_volume is defined in the first line with its parameters.
  2. The subsequent line calculates the volume of a rectangular-based pyramid using the equation V = l * w * h / 3.
  3. Finally, the calculated volume is returned.

The output displayed below demonstrates the function's result with inputs 4.5, 2.1, and 3.0.

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An air duct heater consists of an aligned array of electrical heating elements in which the longitudinal and transverse pitches
Kisachek [338]

Answer:

a) q = 7671 W

T0 = 47.6°C

b) ΔP = 202.3 N/m²

P = 58.2 W

c) hDarray = 2 times hD of an isolated element.

Explanation:

see the image for the solution.

4 0
29 days ago
A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7
mote1985 [299]

Answer:

r=0.31

Ф=18.03°

Explanation:

Provided:

Original diameter of bar = 75 mm

Diameter post-cutting = 73 mm

Average diameter of the bar d= (75+73)/2=74 mm

Average length of uncut chip = πd

Average length of uncut chip = π x 74 =232.45 mm

Thus, cutting ratio r

Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}

r=\dfrac{73.5}{232.45}   r=0.31

Therefore, the cutting ratio equals 0.31.

Now, the shearing angle is given as

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

Next by substituting the values

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }\

Ф=18.03°

Concluding, the shearing angle is 18.03°.

4 0
1 month ago
Given num_rows and num_cols, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print
Viktor [368]

Answer:

This is the solution code in Python:

  1. alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J']
  2. user_input = input("Enter number of rows and columns: ")
  3. myArr = user_input.split(" ")
  4. num_rows = int(myArr[0])
  5. num_cols = int(myArr[1])
  6. seats = []
  7. for i in range(num_rows):
  8. row = []
  9. for j in range(num_cols):
  10. row.append(alphabets[j])
  11. seats.append(row)
  12. output = ""
  13. for i in range(len(seats)):
  14. for j in range(len(seats[i])):
  15. output += str(i + 1) + seats[i][j] + " "
  16. print(output)

Explanation:

Initially, we create a small list of alphabets from A to J (Line 1).

We then request the user to enter the number of rows and columns (Line 3). Given that the input comes as a string (e.g., "2 3"), we utilize the split() method to separate the numbers into individual items in a list (Line 4). The first item (row number) is assigned to variable num_rows, while the second item (column number) goes to num_cols.

Subsequently, we construct the seats list with a nested for-loop (Lines 10-15). Once the seats list is formed, another nested for-loop generates the required output string as per the question (Lines 19-21).

Finally, the output is printed (Line 23). For example, an input of 2 3 results in the output:

1A 1B 1C 2A 2B 2C

8 0
1 month ago
A well-insulated rigid tank contains 1.5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters o
Daniel [317]

Answer:

The change in entropy of the steam is 2.673 kJ/K

Explanation:

The mass of the liquid-vapor mixture is 1.5 kg

The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg

The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg

According to the steam tables

At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK

The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K

6 0
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Answer:I want to know what game to play?

Explanation:

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1 month ago
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