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Iteru
1 month ago
5

Joseph drove to Carly’s house for dinner. He was away from his house for 2 hours. He spent 50minutes at Carly’s house. Driving t

o and from Carly’s house he drove at a speed of 45mph. How far away from Carly does Joseph live?
Mathematics
1 answer:
Svet_ta [12.7K]1 month ago
7 0

70 miles

I hope this information is helpful

-Millie

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Question:

Which statement is accurate concerning the function’s discontinuities f(x) = \frac{x-5}{3x^2-17x-28}

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

Goal:

Identify the correct statement

f(x) = \frac{x-5}{3x^2-17x-28}

We need to factor the denominator first.

f(x) = \frac{x-5}{(3x+4)(x-7)}

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

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x = 7

Next, evaluate the limit when (x = \frac{-4}{3}) and at (x = 7)

lim f(x) as (x = \frac{-4}{3}) = ±∞

lim f(x) as (x=7) = ±∞

Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at (x = \frac{-4}{3}) and x=7

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Answer:

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(b)

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Step-by-step explanation:

The information provided states:

The distance from A to B is 15 yards.

Thus, AB is 15 yards.

The distance from B to C is 25 yards.

Therefore, BC is 25 yards.

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The total distance from A to B to C is given by AB plus BC.

A to B to C = 15 + 25.

The total distance is 40 yards.

(b)

The direct distance from A to C (AC) must be shorter than the length of A to B to C.

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You have two kinds of data $ and %!
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