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LuckyWell
9 days ago
6

a professional baseball player can pitch a baseball with a velocity of 44.7m/s towards home plate. If a baseball weighs 1.4 N, h

ow much momentum does it have when it hits the catcher units
Physics
2 answers:
inna [987]9 days ago
8 0

Result:

p = 6.25 kg-m/s

Detail:

The baseball's velocity is given as v = 44.7 m/s

The weight of the baseball is W = 1.4 N

First, we must determine the baseball's mass, calculated as:

m=\dfrac{W}{g}

m=\dfrac{1.4\ N}{9.8\ m/s^2}

m = 0.14 kg

The momentum of a body is the product of its mass and speed, represented as:

p=m\times v

p=0.14\ kg\times 44.7\ m/s

p = 6.25 kg-m/s

Thus, the momentum it has when reaching the catcher is 6.25 kg-m/s. This is the answer.

Sav [1.1K]9 days ago
3 0
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
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Answer:

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Explanation:

Given that,

Moles present = 3

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Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

\Delta H_{1}=nC_{p}\times\Delta T

Substituting the values into the equation

\Delta H_{1}=3\times6.9\times(320-300)

\Delta H_{1}=414\ cal

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\Delta H_{1}=nC_{v}\times\Delta T

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\Delta H_{1}=3\times4.9\times(300-320)

\Delta H_{1}=-294\ cal

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Using the total heat formula

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\Delta H_{T}=414-294

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A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0.36
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Response:

0.60 m/s

Details:

The average speed between times t = a and t = b can be expressed as:

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Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart
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Answer:F=\frac{(M+m)g}{\mu _s}

Explanation:

Provided:

The trolley, with mass M, is allowed to roll freely without friction.

The coefficient of friction between the trolley and mass m is \mu _s.

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