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Alik
13 days ago
14

The density of benzene at 15°C is 0.8787g/mL calculate the mass of 0.1300 of benzene at this temperature

Chemistry
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Which statement is TRUE regarding the macroscopic and
lions [2927]

Answer:

Chemists observe phenomena on a macroscopic level which informs their understanding of microscopic aspects.

Explanation:

Many critical chemical insights arise from macroscopic observations because most scientific instruments currently cannot directly evidence microscopic events. Data gathered from these larger-scale observations can yield valuable insights into the nature of specific microscopic interactions.

This is particularly true in atomic structure studies. The majority of evidence that contributed to our understanding of atomic structure was obtained from macroscopic observations and subsequently provided crucial information regarding the atom's microscopic configuration.

7 0
2 months ago
Is N2 + H2 →NH4 a balanced chemical equation? Is it obeying the law of conservation of matter?
eduard [2782]
The response is:

No, the equation is not balanced. Neither the Nitrogen (N) nor the Hydrogen (H) are in balance!

Here's the reasoning:

⓵ A properly balanced chemical equation means that the quantity of atoms on the reactants side matches that on the products side.

→ The equation lacks balance because there are 2 Nitrogen atoms and 2 Hydrogen atoms on the reactants side. In contrast, on the products side, there is only 1 Nitrogen atom and 4 Hydrogen atoms. Thus, the number of atoms on each side is not consistent!

Hopefully, this clarification is helpful; feel free to reach out if you have any further questions! ☻
8 0
2 months ago
If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.50 mol
castortr0y [3046]
684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
7 0
2 months ago
Calculate the grams of oxygen in 90.0 g of cl2o
lorasvet [2795]
To find the mass of oxygen in the specified compound, we require the molar mass for both the compound and oxygen. We also establish the relationship between the number of moles of oxygen per mole of the substance. The calculation proceeds as follows:

90.0 g ( 1 mol / 86.91 g ) ( 1mol O / 1 mol Cl2O) ( 16 g / 1 mol ) = 16.57 g O


4 0
2 months ago
Read 2 more answers
What is the molarity of 200 ml of solution in which 2.0 moles of sodium bromide is dissolved?
eduard [2782]
Molarity is calculated using moles divided by the volume in liters. Convert 200 mL to 0.2 L, then divide 2 moles by 0.2 L.
7 0
2 months ago
Read 2 more answers
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