In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form
ed during the reaction. A cross drawn at
the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial
record of the experiment is shown
Experimental Record
Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete
sentences to explain the trend you predicted. You do not have to determine exact values for time, just describe the trend you would expect (increase or decrease)
and why it occurs
the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial
record of the experiment is shown
Experimental Record
Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete
sentences to explain the trend you predicted. You do not have to determine exact values for time, just describe the trend you would expect (increase or decrease)
and why it occurs
1 answer:
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Answer:
0.133
Explanation:
The reaction that occurs between KIO3 and KI in an acidic medium is described as
IO3⁻ +5I⁻ +6h⁺ → 3I₂ + 3H₂O
I₂ subsequently reacts with sodium thiosulfate
NaS₂O₃ → 2Na⁺ + S₂O₃²⁻
The overall reaction can be summarized as
IO⁻₃ + 6H⁺ + 6S₂O₃³⁻ → I⁻ + 3S₄O₆²⁻ + 3H₂O
The mole of KIO₃
is computed using molarity multiplied by volume
which equals 0.00002mol
One mole of KIO₃ reacts with 6 moles of S₂O₃²⁻
which gives 2x6x10⁻⁵
= 0.00012 molThe volume is 0.90 ml1 ml equals 0.001L0.90ML is 0.0009LTo find concentration,
molarity/volume= 0.00012/0.0009= 0.133m