You are in a hot-air balloon that, relative to the ground, has a veloc- ity of 6.0 m/s in a direction due east. You see a hawk m

The force is calculated by multiplying mass and gravitational acceleration (F= mg). To find the solution, the mass of the elephant (5600 kg) is multiplied by gravity (9.8 m/s²). The result is 55,880 N, representing the upward gravitational force the elephant exerts on the Earth.

Answer:

a) Ф = 0.016 N / C m, b) q_{int} = 0.14 10⁻¹² C

Explanation:

a) For this scenario, we rely on Gauss's law

          Ф = E.ds = /ε₀

As the field points in the x direction, there is no flux through the cylinder walls.

          Ф = E A

         

The area of a circle is

           A = π r

          Ф = E π r

          Ф = (x- 3.6) r

Now, let's compute

          Ф = (3.7 -3.6) 0.16

          Ф = 0.016 N / C m

     

b) Using Gauss's law, we have

             q_{int} = Ф ε₀

 

Where the flow is present on both sides, at the face corresponding to x = 0, the flow is zero

             q_{int} = 0.016 8.85 10⁻¹²

             q_{int} = 0.14 10⁻¹² C

To begin, let's state the facts: the tennis ball weighs 0.003 kg, while the soccer ball weighs 0.43 kg, and both are moving at the same speed of 16 m/s. The formula for momentum is P=MV where P stands for Momentum, M for Mass, and V for Velocity. Now, let's calculate the momentum for the tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ). I denote tennis ball momentum with a subscript "t." For the soccer ball, the momentum is Ps= 0.43 x 16 m/s = (      km-m/s). When we assess the momentum between the two balls, the heavier one will typically exhibit more momentum owing to its greater mass, unless the tennis ball, having less mass, achieves a higher velocity to match or exceed the momentum of the soccer ball.

Answer:

times

Explanation:

To approach this question, we first express the universe's age and the top quark's lifespan in scientific notation.

Age of the universe:

(1 followed by 17 zeros)

Lifetime of the top quark:

(the decimal point is shifted 24 places to the right)

To provide an answer, we will compute the ratio of the age of the universe to the lifespan of the top quark:

Answers:

1. To begin with, we need to clarify that Pressure is defined as the Force applied divided by the area . This can be mathematically formulated as follows:

  (1)

The unit for Pressure is Pascal (Pa), which corresponds to and is also equivalent to

Another formulation for Pressure considers the density  of the liquid, its height within the container, and the force due to gravity :

    (2)

In this scenario, the liquid in question is water, with a known density of roughly:

Thus, we need to input the values into equation (2) to find the pressure (make sure to check the units):

Next, substitute this value into equation (1) to isolate :

In conclusion:

2. For this problem, we will apply equation (1) to determine the Pressure. We already have the area and the force applied by the water in the container :

3. Here, equation (2) is ideal for calculating the hydrostatic pressure at any point located at the bottom of the tank (be cautious with your units):

     

     

4. In this situation, it's critical to note that in fluids (specifically water here), higher fluid levels result in reduced pressure. Therefore, if and denote the pressures at heights and , respectively, and recognizing that the density of water and gravitational force remain constant, we can employ the following equation for our solution:

  (3)

Where:

at

It's noteworthy that

And is the variable at a specific height

Now we can substitute the known values into equation (3) to compute :

   

In conclusion:    

5. In this scenario, we have the area and the mass of the piston , and our goal is to find the pressure .

We'll utilize equation (1):  

However, do you recall that we mentioned earlier that pressure is defined as the force exerted over an area?

In this instance, we will apply the following equation that incorporates both the gravitational force and the mass of an object to determine :

Subsequently:

Now we are able to perform the calculation for :