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28 days ago

Callie did a lab during which she investigated the difference in cellular respiration rates between two different types of corn:

germinating and non-germinating. A germinating seed is one from which plant has started to grow. A non-germinating seed is usually dry, and a new plant has not yet emerged.The data that she gathered is displayed in the graph below.
Which of the following statements are true concerning the data that Callie gathered during the lab? Choose the two that apply.
A.The germinating corn seed produced more energy than the non-germinating corn seed.
B.The non-germinating corn seed produced more carbon dioxide than the germinating corn seed.
C. The germinating corn seed consumed more oxygen than the non-germinating corn seed.
D. The non-germinating corn seed performed more cellular respiration and the germinating corn seed.
E. The non-germinating corn seed performed cellular respiration and the germinating corn seed performed fermentation.
Please I NEED the TWO ANSWERS ASAP!

Physics

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A metal, M, forms an oxide having the formula M2O3 containing 52.92% metal by mass. Determine the atomic weight in g/mole of the

ValentinkaMS [3465]

Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

52.92% metal: 52.92 g M
47.80% oxygen: 47.80 g O

By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

$moles of oxygen=\frac{47.8g*1mol}{16g}$

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

$2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M$

Given 52.92 g of metal in the sample, the molar mass of the metal is:

$molar mass=\frac{52.92 g}{5.975 mol}$

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

3 0

2 months ago

You are at a train station, standing next to the train at the front of the first car. The train starts moving with constant acce

serg [3582]

The duration required for the seventh car to pass amounts to 13.2 seconds. The train's movement is characterized by uniform acceleration, enabling the application of suvat equations. Initially, we analyze the movement of the first car, utilizing the equation for distance s covered in time t, which corresponds to the length of one car, with u = 0 as the initial velocity and a representing acceleration, over t = 5.0 s. We can rearrange the equation reflecting L as the length of one car. This is similarly applicable for the initial seven cars, accounting for the distance of 7L and the required time t'. With constant acceleration retained, we can derive t' through substitution in the equation, leading to fundamental conclusions regarding the relationship exhibited in the graph of distance against time in uniformly accelerated motion.

8 0

2 months ago

A vector A is added to B=6i-8j. The resultant vector is in the positive x direction and has a magnitude equal to A . What is the

Yuliya22 [3333]

The answer is letter d, 8.3.

Here’s a solution for the given problem:

We have:

B = 6i - 8j

Let A be unknown; we'll denote A as = mi + nj

The resultant A+B lies along the x-axis (which implies A+B = Ki + 0j, where K is yet to be determined,

and we also know the magnitude of A+B is equivalent to the magnitude of A,

therefore, mag(A+B)=K=sqrt(m^2+n^2), or K^2 = m^2+n^2.

Using vector addition, A+B becomes (m+6)i + (n-8)j.

Since we know A+B = Ki + 0j, we can establish that:

m + 6 = K

n - 8 = 0, which gives n=8.

Thus, K^2=m^2+n^2 means (m+6)^2 = m^2 +8^2

= m^2 + 12m + 36 = m^2 + 64

which gives us 12m = 28

m = 2.33333...

Consequently, the magnitude of A is sqrt[(2.333...)^2 + 8^2] = 8.3333.

5 0

3 months ago

Read 2 more answers

In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t

Keith_Richards [3271]

Answer:

$E_t_o_t_a_l=7.603MJ$

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, $W$ , is linked to its specific mechanical power. $Mechanical \ power$ calculated per unit mass can be derived from the following equation:

$\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ$

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

6 0

3 months ago