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Roman55
11 days ago
10

A rancher has 1,800 linear feet of fencing and wants to enclose a rectangular field and then divide it into two equal pastures w

ith one internal fence parallel to one of the rectangular sides. what is the maximum area of each pasture? 5400
Mathematics
1 answer:
Svet_ta [4.3K]11 days ago
5 0
Answer: 67.500 ft²

Explanation:

1) Assign variables to the dimensions:

y: length of the rectangular area
x: width of the rectangular area

2) Model the fencing required for the two identical pastures:

two widths plus one divider fence: 2x + x = 3x
two lengths: 2y

⇒ 3x + 2y = 1800 ← total linear feet of fencing

y = 1800 / 2 - 1.5x ← isolating y

y = 900 - 1.5x

3) Area calculation for each pasture

A = x(y/2)      ← equivalent to half of xy

A = x (900 - 1.5x) ← substituting y with 900 - 1.5x

A = 900x - 1.5x² ← applying the distributive property

4) Maximum area ⇒ A' = 0

A' = 900 - 1.5x ← derivative of the polynomial 900x - 1.5x²

900 - 1.5x = 0

⇒ 1.5x = 900

⇒ x = 900/1.5

⇒ x = 600

4) Calculate y

y = 900 - 1.5x = 900 - 1.5(600) = 900 - 900 = 0

5) Calculate the area of each pasture

A = xy/2 = 600 × 0 / 2 = 0 ← final answer
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