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Fofino
6 days ago
13

How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?

Chemistry
1 answer:
lions [2.6K]6 days ago
6 0
I believe you mean KO2 reacting with H2O. The reaction is 4KO2+2H2O->4KOH +3O2. The mole ratio O2:KO2 is 3:4. Thus moles of O2 produced = 0.500/4*3 = 0.375 mol.
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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
KiRa [2711]
To determine the specific heat capacity of the metal and assist in its identification, the heat absorbed by the calorimeter can be computed using: Energy = mass * specific heat capacity * temperature change Q = 250 * 1.035 * (11.08 - 10) Q = 279.45 cal/g. Next, we employ the same formula for the metal because the heat taken in by the calorimeter should equal the heat expelled by the metal. -279.45 = 50 * c * (11.08 - 45) [the minus sign indicates energy release] solving for c gives us 0.165. Therefore, the specific heat capacity of the metal amounts to 0.165 cal/g°C.
6 0
22 days ago
Read 2 more answers
What percent, by mass, is Oxygen in the compound Fe(OH)3?
Anarel [2600]

Answer:

Oxygen's mass percent in Fe(OH)3 is 44.92%

Explanation: The mass percentage is a means of indicating the concentration of a specific element within a compound. It is determined through the ratio of the element's mass to the compound's total mass, multiplied by 100.

•First calculate the overall mass of the compound

•Fe's molar mass = 55.85 g/mol

•O's molar mass = 16 g/mol

•H's molar mass = 1 g/mol

Using these values, we can compute the molecular mass of Fe(OH)3 = 55.85 g/mol + (16 g/mol)3 + (1 g/mol)3

=55.85 g/mol + 48 g/mol + 3 g/mol

=106.85 g/mol

Mass percent of an element = mass of element/total mass of compound × 100

In the case of 3 oxygen atoms present within the compound, the mass of oxygen totals 48 g/mol

Mass percent of oxygen= 48 g/mol/106.85 g/mol × 100

= 0.4492×100= 44.92%

[[TAG_31]]Thus, the mass percent of oxygen in Fe(OH)3 amounts to 44.92%[[TAG_32]]
7 0
11 days ago
A 250 ml flask contains 3.4 g of neon gas at 45°c. Calculate the pressure of the neon gas inside the flask.
eduard [2509]
The solution to your inquiry yields P = 17.73 atm. Explanation: The volume V is 250 ml, equivalent to 0.25 liters (L), with a mass of 3.4 g and a temperature of 45°C, which converts to 318°K. We utilize the ideal gas law PV = nRT for the calculations.
7 0
8 days ago
Montrel takes a trip to Central America during the winter. He finds out that the temperature in Central America is about the sam
lorasvet [2515]

Answer:

C

Explanation

My teacher mentioned that, for instance, Florida tends to be warm, while Central America can have both hot and cold temperatures, and a jacket isn't necessary. I don't recall many details.

6 0
29 days ago
Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of co2 and 0.1451 g of h2o. wha
VMariaS [2690]
CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O

m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}

0.2845/{44.01x}=0.1451/{9.01y}

x/y=0.4=2:5

The empirical formula is C₂H₅.
7 0
1 month ago
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