Air, modeled as an ideal gas, is compressed at steady state from 1 bar, 300 K, to 5 bar, 500 K, with 30 kW of power input. Heat

Answer:

18.7 mm

Explanation:

The law of heat conduction as described by Fourier for a plate is:

q = -k/t * ΔT

In this equation

q: heat transfer per unit time and area

k: coefficient of thermal conductivity

t: plate's thickness

ΔT: difference in temperature

By rearranging the terms, we find:

t = -k/q * ΔT

t = -1.4/(-1200) * 16 = 0.0187 m = 18.7 mm (the negative value of q indicates heat is being released from the plate)

Thus, the concrete slab can have a maximum thickness of 18.7 mm.

Answer:

The highest vehicle count = 308

Explanation:

Refer to the attached document for the calculations.

Answer:

153.2 J

Explanation:

Let’s first identify our known variables:

mass (m) of the block = 10 kg

distance slid down (i.e., displacement) = 2 m

coefficient of kinetic friction (μk) = 0.2

In the following diagram, if we analyze the force component directed along the displacement, we find

Fcos 40°

100 (cos 40°)

76.60 N

The work done by the frictional force is then calculated as:

W = × displacement

W = 76.60 × 2

W = 153.2 J

Therefore, the work done by the frictional force equals 153.2 J

Answer:I want to know what game to play?

Explanation:

Answer:

Total bandwidth: 8 kHz

Explanation:

Data provided:

Transmitter frequency: 3.9 MHz

Modulation up to: 4 kHz

Solution:

For the upper side frequencies:

Upper side frequencies = 3.9 × + 4 × 10³

Upper side frequencies = 3.904 MHz

For the lower side frequencies:

Lower side frequencies = 3.9 × - 4 × 10³

Lower side frequencies = 3.896 MHz

Consequently, the total bandwidth is computed as:

Total bandwidth = upper side frequencies - lower side frequencies

Total bandwidth = 8 kHz