A vessel contained N2, Ar, He, and Ne. The total pressure in the vessel was 987 torr. The partial pressures of nitrogen, argon,

Answer:

For A: The change in free energy for the reaction is -5339.76 J/mol

For B: Free energy change is expressed in kJ/mol

For C: The forward reaction favors progression, while the reverse reaction does not.

Explanation:

Regarding the specified chemical reaction:

• For A:

The relationship between standard Gibbs free energy and equilibrium constant is as follows:

The free energy change can be calculated using the following equation:

Or,

where,

= Change in free energy

R = Gas constant =

= standard temperature =

T = temperature of the cell =

= equilibrium constant =

Q = reaction quotient =

= 0.06 M

[DHAP] = 0.125 M

Substituting the values into the equation yields:

Thus, the change in free energy for the reaction is -5339.76 J/mol

• For B:

To convert the free energy change to kilojoules, we apply the conversion factor:

1 kJ = 1000 J

So,

Consequently, the free energy change's units are kJ/mol

• For C:

For spontaneity in the reaction, the Gibbs free energy must be negative. However, the calculations indicate a positive Gibbs free energy, leading to the conclusion that the reaction is not spontaneous.

The free energy change of the reaction is negative.

Consequently, the forward reaction is favored and the reverse reaction is not favored.

The result is 14.5 g L⁻¹. Here, the problem indicates to reduce the units to one. The existing units are g/L. To achieve a singular unit format, we can move L to the numerator, which can be executed as per the exponent laws; specifically, 1 / aˣ = a⁻ˣ. Thus, we can express 1 / L as L⁻¹. Consequently, the simplified unit remains g L⁻¹. However, remember to leave a space between two different units. This ultimately depicts a unit of density.

The atomic number of the element indicated by the model is 8, corresponding to option 'C' in the question.

Answer:

(C) The average speed of molecules in ethane is the same as that of propanol.

Explanation:

In gas behavior, temperature is directly linked with speed. At a constant temperature, speed remains consistent. Also, we understand that ideal gases exhibit uniform behavior, irrespective of their type.

Although I may not be the smartest, I can definitely answer.

This represents a chemical change because the substances' chemical identities were altered. The fizzing was a clear sign, and the temperature increase was another indicator of the reaction.