Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy

Answer:

Statements 4, 6 & 7 are incorrect.

Explanation:

In any elastic collision, the overall momentum vector sum of the system remains zero.

In this scenario, an elastic collision occurs between the ball and a stationary wall. The ball's velocity will consistently revert after the impact, leading to a change in direction of momentum.

The initial momentum of the ball is represented as:

where:

m = mass of the ball

v = initial velocity of the body

post-collision for the elastic interaction:

• Here, the momentum changes solely in direction, thus contradicting statement 7.

• During the impact, both the ball and the wall exert forces on each other that are equal and opposite. The wall remains motionless, while the ball is influenced by the wall's reaction force, performing work on it, which contradicts statement 4.

• Given that this collision is elastic, the ball's form and dimensions do not alter.

• The previous points clearly indicate that not all provided statements hold true, thus violating statement 6.

Response:

A=0.199

Clarification:

We know that  

Mass of spring=m=450 g=

Where 1 kg=1000 g

To determine the amplitude of oscillations.

Energy for oscillator=

Where =Angular frequency

A=Amplitude

Using the formula

Therefore, the amplitude of oscillation=A=0.199

According to Newton's second law, provided F is directed horizontally,

• the net horizontal force acting on the larger block is

F - µmg = 3mA

where µmg represents the friction experienced by the larger block from contact with the smaller block, µ is the static friction coefficient between both blocks, and A indicates the acceleration of the block;

• the net vertical force on the larger block is

4mg - 3mg - mg = 0

where 4mg denotes the magnitude of the normal force exerted by the surface on the combined mass of both blocks, 3mg corresponds to the weight of the larger block, and mg indicates the weight of the smaller block;

• the net horizontal force acting on the smaller block is

µmg = ma

where µmg again signifies the friction between both blocks; however, it is important to note that this force aligns in the same direction as F. It is the sole force influencing the smaller block in the horizontal direction, thus (b) static friction causes the smaller block's acceleration;

• the net vertical force on the smaller block is

mg - mg = 0

where mg represents the force of both the normal force from the larger block pushing up against the smaller one, and the weight of the smaller block.

(You should be able to create your own free-body diagrams based on the forces discussed.)

(c) Solve the equations stated above to find A and a:

A = (F - µmg) / (3m)

a = µg

Heat supplied to the gas = Q = 743 Joules

Work applied to the gas = W = -743 Joules

Additional explanation

The Ideal Gas Law that should be remembered is:

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Now, let’s proceed with the problem!

Given:

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

Unknown:

Work done on the gas = W =?

Heat supplied to the gas = Q =?

Solution:

Step A:

An ideal gas expands isothermally:

Next, we will determine the work performed on the gas:

Step B:

By utilizing the methodology mentioned earlier:

Next, we will ascertain the work completed on the gas:

Ultimately, we can calculate the total work done and heat supplied as follows:

Learn more

• Minimum Coefficient of Static Friction:
• The Pressure In A Sealed Plastic Container:
• Effect of Earth’s Gravity on Objects:

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

Answer:

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

where

indicates the alteration in length of the object

signifies the object's initial length

In this case, we have and , hence the strain is