Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy

1 answer:

8 0

The energy contained in a photon is determined by the formula:
$E=hf$
where h represents the Planck constant and f signifies the frequency of the photon. Given the energy of the photon, $E=3.26 \cdot 10^{-19} J$ , we can rearrange the equation to deduce the photon's frequency:
$f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz$

Now, we can use the relationship that links frequency f, wavelength $\lambda$ , and the speed of light c to ascertain the wavelength of the photon:
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm$

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