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10 days ago

Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy

1 answer:

8 0

The energy contained in a photon is determined by the formula:
$E=hf$
where h represents the Planck constant and f signifies the frequency of the photon. Given the energy of the photon, $E=3.26 \cdot 10^{-19} J$ , we can rearrange the equation to deduce the photon's frequency:
$f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz$

Now, we can use the relationship that links frequency f, wavelength $\lambda$ , and the speed of light c to ascertain the wavelength of the photon:
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm$

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The Hall effect can be used to calculate the charge-carrier number density in a conductor. If a conductor carrying a current of

kicyunya [1025]

Answer:

$6.6*10^{27}e/m^3$

Explanation:

When calculating Hall voltage, it is crucial to have the current, magnetic field strength, length, area, and number of charge carriers available. The Hall voltage can be expressed using the equation:

$V_h = \frac{iB}{neL}$

Where:

i= the current

B= the magnetic field strength

L = the length

n = the number of charge carriers

e= charge of an electron

We need to replace values and solve for n:

$n= \frac{iB}{V_h e L}$

$n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}$

$n= 6.6*10^{27}electron.m^{-3}$

As a result, the charge carrier density is $6.6*10^{27}e/m^3$

5 0

7 days ago

An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista

Sav [1105]

Answer:

h = 12.8 cm

Explanation:

The initial parameters are as follows:

distance = 6.4 cm

when the object descends, its weight matches the spring's force

weight = spring force

mg = ky... equation 1

potential energy stored in a stretched spring = work done by the spring

mgh = 0.5 x k x h^{2}....equation 2

Substituting from equation 1 into equation 2

kyh = 0.5 x k x h^{2}

y = 0.5 x h

2y = h

where y is 6.4, yielding the maximum elongation as

h = 2 x 6.4 = 12.8 cm

6 0

5 days ago

Bursitis can affect many joints and can be caused by a numerous sporting activities, such as cycling, tennis, and long-distance

Yuliya22 [1153]

Bursitis refers to the irritation or injury of the small fluid-filled sacs called bursae that are located around the joints. This condition can lead to pain during movement or when the affected area is pressed. Occasionally, a rash may also develop. Thank you for your inquiry; I trust this information will be beneficial.

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4 days ago

Read 2 more answers

Compare the time period of two simple pendulums of length 4m and 16m at a place.

Ostrovityanka [942]

Answer:

The period of the pendulum measuring 16 m is double that of the 4 m pendulum.

Explanation:

Recall that the period (T) of a pendulum with length (L) is defined by:

$T=2\,\pi\,\sqrt{ \frac{L}{g} }$

where "g" denotes the local gravitational acceleration.

Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:

$T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2$

Thus, the duration of the 16 m pendulum is two times that of the 4 m one.

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3 days ago

For a projectile, which of the following quantities are constant during the flight: x, y, vx, vy, v, ax, ay? Check all that appl

Yuliya22 [1153]

Response:

C. vx

F. ax

G. ay

Clarification:

The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.

Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.

The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.

Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.

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7 days ago