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8 days ago

A signalized intersection approach has three lanes with no exclusive left or right turning lanes. The approach has a 40-second g

reen out of a 75-second cycle. The yellow plus all-red intervals for phase total 4.0 seconds. If the start-up lost time is 2.3s/phase, the clearance lost time is 1.1s/phase, and thesaturation headway is 2.48 s/veh under prevailing conditions, what is the capacity of the intersection approach?

Engineering

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simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The

iogann1982 [368]

A.) 591.7 v B.) 991.7 v C.) 59.7 % D.) 47.9 kW E.) 247925 W F.) 59.7 %

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2 months ago

3/63 A 2‐kg sphere S is being moved in a vertical plane by a robotic arm. When the angle θ is 30°, the angular velocity of the a

Kisachek [356]

Answer:

Ps=19.62N

Explanation:

A thorough explanation of the answer can be found in the attached files.

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3 months ago

An insulated box containing helium gas falls from a balloon 4.5 km above the earth's surface. calculate the temperature rise in

iogann1982 [368]

The increase in temperature of the helium gas is calculated to be 14.25 K. The helium is located in an insulated box that falls from a height of 4.5 km. As it descends, the potential energy is transformed into internal energy of the helium gas. The equation for temperature change can be expressed as: 10 x 4.5 = 3.15 x ΔT, yielding a temperature increase of ΔT = 14.25 K.

6 0

2 months ago

6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20

Viktor [391]

Explanation:

At a temperature of $33^{\circ} C$ and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.

At a temperature of $33^{\circ} C$ and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.

To determine the mass of air, the following formula can be used:

$\begin{aligned}m _{1} &=\frac{ v }{ v }(1- w ) \\&=\frac{1 \times 10^{5}}{13.535}(1-0.0066) \\&=7339.49 lb / min \\v _{ a } &=\frac{ m _{1} v }{(1- w )} \\v _{ a } &=\frac{7339.49 \times 14.289}{(1-0.0223)} \\v _{ a } &=107266.0 ft ^{3} / min\end{aligned}$

Now, we will calculate the volume

$\begin{aligned}m _{ w } &=\frac{ v _{ a }}{ v _{ a }} w _{ a }-\frac{ v _{ i }}{ v _{ i }} w _{ i } \\&=\frac{107266.0}{14.289} \times 0.0223-\frac{100000}{13.535} \times 0.0066 \\&=118.64 lb / min\end{aligned}$

The duration required to fill the cistern can be determined with the equation:

$Time $=\frac{\text { cistern volume }}{\text { removal water perminute volume }}$$

By substituting the values into the preceding formula, we find:

$$\frac{\left(15 \times 10^{3} L\right) \times\left(0.0353147 ft ^{3} / L \right)}{(118.641 b / min ) \times\left(\frac{1}{62.41 lb / ft ^{3}}\right)}$\\$=279.09$ minutes\\$=4.65$ hours.$

Thus, the hours necessary to fill the cistern amount to 4.65 hours.

3 0

2 months ago

Dust,dirt, or metal chips can pose a potential what kind of injury risk in a shop

Viktor [391]

Answer:

In a workshop, there is a risk of eye injury from dust, dirt, or metal shavings.

Explanation:

5 0

1 month ago