84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.
Explanation:
Balanced equation:
2 Fe + 3 Cl2 → 2 FeCl3
DATA PROVIDED:
iron = atoms
mass of chlorine = 67.2 liters
mass of FeCl3 =?
The number of moles of iron will be calculated as
number of moles = 
number of moles = 
number of moles = 0.52 mol of iron
moles of chlorine gas
number of moles = 
Substituting the values into the equation:
n = 
(molar mass of chlorine gas = 70.96 g/mol)
= 947.01 moles
As iron is the limiting reagent therefore
2 moles of Fe lead to 2 moles of FeCl3
0.52 moles of Fe will yield
= 
0.52 moles of FeCl3 is produced.
To express this in grams:
mass = n x molar mass
= 0.52 x 162.2 (molar mass of FeCl3 is 162.2g/mol)
= 84.34 grams
Answer:
Endothermic: water formation from ice and a cold instant ice pack Explanation:
The ore contains a 55.4% composition of calcium phosphate (related to apatite), leading to a calculation where Ca3(PO4)2 equals 55.4%x=1000g, resulting in x=1000/0.554, which equals 1.805kg. To find the percentage of phosphorus in this amount of calcium phosphate, calculate the total masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (noting that oxygen contributes 16 mass x 4 =64), giving a cumulative mass of 310.2, while the phosphorus is 61.95 (Pmass x 2). Therefore, 61.95/310.2= 0.19 or 19% for phosphorus. Consequently, from 1.805 x 0.19, there will be 0.34kg of phosphorus.
