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14 days ago

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The path of a particle is defined by y = 0.5x2. If the component of its velocity along the x-axis at x = 2 m is vx = 1 m/s, its

velocity component along the y-axis at this position is ____.

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If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.

ValentinkaMS [3465]

V = I * R, where V signifies voltage, I represents current, and R is resistance. According to Ohm's law, to determine the current through the wire, resistance is required. In theory, if the wire had zero resistance, it would lead to infinite current, which is not feasible. This negligible resistance could refer to the internal resistance of the battery rather than the wire itself.

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2 months ago

A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f

kicyunya [3294]

Answer:

$\Delta T = 0.81 ^oC$

Explanation:

According to the principle of energy conservation

all kinetic energy will change into thermal energy to increase its temperature

$\frac{1}{2}mv^2 = ms\Delta T$

Next, divide both sides by the object's mass

$\frac{1}{2}v^2 = s\Delta T$

the resulting temperature change is expressed as

$\Delta T = \frac{v^2}{2s}$

$\Delta T = \frac{25^2}{2\times 387}$

$\Delta T = 0.81^oC$

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2 months ago

A conducting sphere 45 cm in diameter carries an excess of charge, and no other charges are present. You measure the potential o

Maru [3345]

Answer:

The excess charge is $Q = 3.5 *10^{-7} \ C$

Explanation:

According to the question, we are informed that

The diameter is $d = 45 \ cm = 0.45 \ m$

The potential of the surface is $V = 14 \ kV = 14 *10^{3} \ V$

The radius of the sphere is

$r = \frac{d}{2}$

by plugging in given values

$r = \frac{0.45}{2}$

$r = 0.225 \ m$

The potential at the surface is mathematically expressed as

$V = \frac{k * Q }{r }$

Where k is Coulomb's constant with a value $k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

Based on the question stating there are no other charges, Q represents the excess charge

Therefore

$Q = \frac{V* r}{ k}$

inserting the numerical values

$Q = \frac{14 *10^{3} 0.225}{ 9*10^9}$

$Q = 3.5 *10^{-7} \ C$

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1 month ago

A 2.0-kg projectile moves from its initial position to a point that is displaced 20 m horizontally and 15 m above its initial po

Yuliya22 [3333]

Answer:

W = 294 J

Explanation:

provided,

mass of the projectile = 2 Kg

horizontal displacement = 20 m

vertical displacement = 15 m

work performed by the gravitational force =?

the work done by gravitational force only accounts for vertical motion.

force due to gravity = m g

= 2 x 9.8 = 19.6 N

work is equal to force x displacement

W = F x s

W = 19.6 x 15

W = 294 J

7 0

2 months ago

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