A box with a mass of 12.5 kg sits on the floor. how high would you need to lift it for it to have a gpe of 355 j
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Answer:
Explanation:
Let T represent the tension in the swing.
At the peak
where v denotes the velocity needed to maintain the circular motion.
r equals the distance from the rotation point to the center of the ball, which is L+\frac{d}{2} (with d being the ball's diameter).
The threshold velocity can be expressed as
To determine the velocity at the bottom, we can use energy conservation principles at both the top and bottom positions.
At the top
Energy at the bottom
By comparing the two states using conservation of energy, we find
Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.