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tamaranim1
2 months ago
7

In root locus technique, angle between adjacent asymptote is (a) 180°/(m+ n) (b) 360°/(m + n) (c) 360°/(m-n) (d) 180°/(m-n)

Engineering
1 answer:
pantera1 [306]2 months ago
4 0

Answer:

Option (d)

Explanation:

Within the root locus technique, the angle between consecutive asymptotes, or the asymptote angle, is determined using this formula:

Angle of asymptote, \angle A = \frac{180^{\circ}(2p + 1)}{m - n}

Assuming p = 0

The equation simplifies to:

\angle A = \frac{180^{\circ})}{m - n}

where

m = number of poles

n = number of zeros

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An air duct heater consists of an aligned array of electrical heating elements in which the longitudinal and transverse pitches
Kisachek [356]

Answer:

a) q = 7671 W

T0 = 47.6°C

b) ΔP = 202.3 N/m²

P = 58.2 W

c) hDarray = 2 times hD of an isolated element.

Explanation:

see the image for the solution.

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1 month ago
Consider 1.0 kg of austenite containing 1.15 wt% C, cooled to below 727C (1341F). (a) What is the proeutectoid phase? (b) How
pantera1 [306]

Answer:

a) The phase before eutectoid is commonly referred to as cementite, with the chemical formula Fe₃C.

b) The total mass of ferrite obtained is 0.8311 kg.

The total cementite mass equals 0.1689 kg.

c) The total cementite mass accounts for 0.9343 kg.

Explanation:

Provided:

1 kg of austenite

a carbon content of 1.15 wt%

Cooled below 727°C

Questions:

a) Identify the proeutectoid phase.

b) Calculate the mass of total ferrite and cementite, Wf =?, Wc =?

c) Determine the mass of both pearlite and the proeutectoid phase, Wp =?

d) Create a schematic to illustrate the resulting microstructure.

a) The proeutectoid phase is referred to as cementite with the formula Fe₃C.

b) To find the total mass of formed ferrite:

W_{f} =\frac{C_{cementite}-C_{2} }{C_{cementite}-C_{1} }

With:

Ccementite = composition of cementite = 6.7 wt%

C₁ = composition of phase 1 = 0.022 wt%

C₂ = overall composition = 1.15 wt%

Inserting the values yields:

W_{f} =\frac{6.7-1.15}{6.7-0.022} =0.8311kg

For the total mass of cementite:

W_{c} =\frac{C_{2}-C_{1}}{C_{cementite}-C_{1} } =\frac{1.15-0.022}{6.7-0.022} =0.1689kg

c) The mass of pearlite:

W_{p} =\frac{6.7-1.15}{5.94} =0.9343kg

d) The diagram illustrates the different compositions: (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)

6 0
2 months ago
Suppose we include the lead resistance in the calculation of temperature for a class A RTD. If R3 = 1000 ohms, Ra = 18 ohms, V0
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Respuesta:

La temperatura máxima que se puede medir (en °C) es 14170.27°C

Explicación:

Los RTDs son termómetros compuestos de metales cuya resistencia aumenta con la temperatura.

Para un RTD de Clase A, l, Alpha = 0.00385.

La fórmula para el RTD es

Rt = Ro ( 1 + alpha x t)

Donde

Rt es la resistencia a la temperatura t°C,

Ro es la resistencia a 0°C

Alpha es un coeficiente de temperatura constante para un RTD de clase A.

Aquí, Rt = 1000ohms,

Ro se considera como Ra = 18Ohms

Por lo tanto,

1000 = 18 ( 1 + 0.00385t)

Dividiendo ambos lados por 18

1 + 0.00385t = 1000/18

0.00385t = 55.55 - 1

0.00385t = 54.55

t = 54.55/0.00385

t = 14170.27°C

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