<span>Only one formula should be applied, and we need to consider ideal gas conditions. This formula is: PV=nRT. Manipulate this equation for the subsequent questions to find the solutions.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Given that the answer in #2 surpasses 269 kPa, the tires are likely to burst.
4. Lower the pressure significantly below the threshold of 269 kPa.</span>
Greetings!
To tackle this question, we will apply the
Henderson-Hasselbach equation and solve for the molar ratio. It’s essential to obtain the pKa value for Acetic Acid, which is listed in reference tables as
4.76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
Thus, the mole ratio of CH₃COOH to CH₃COONa is
5.75Wishing you a wonderful day!