Response:
The specific heat of the alloy 
Clarification:
Weight of the alloy 
= 25 gm
Initial temperature 
= 100°c = 373 K
Weight of the water 
= 90 gm
Initial temperature of water 
= 25.32 °c = 298.32 K
Final temperature 
= 27.18 °c = 300.18 K
Using the energy balance equation,
Heat released by the alloy = Heat absorbed by the water
[[ - ] = 
( - )
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This gives us the specific heat of the alloy.
Answer:
In all listed reactions, ΔH°rxn does not correspond to the ΔH°f of the resulting product.
Explanation:
The standard enthalpy of formation (ΔH°f) signifies the enthalpy change that occurs when 1 mole of a product is created from its basic elements in their standard states.
1/2 O₂(g) + H₂O(g) ⟶ H₂O₂(g)
ΔH°rxn does not equal ΔH°f of the product, since H₂O(g) is a compound rather than an element.
Na⁺(g) + F⁻(g) ⟶ NaF(s)
ΔH°rxn is not the same as ΔH°f of the product because Na and F are not in their standard states (Na(s); F₂(g)).
K(g) + 1/2 Cl₂(g) ⟶ KCl(s)
ΔH°rxn is not equal to ΔH°f of the product due to K being outside its standard state (K(s)).
O₂(g) + 2 N₂(g) ⟶ 2 N₂O(g)
ΔH°rxn does not match ΔH°f of the product as 2 moles of N₂O are produced.
In none of the above cases does ΔHrxn match ΔHf of the product.
The response is:
No, the equation is not balanced. Neither the Nitrogen (N) nor the Hydrogen (H) are in balance!
Here's the reasoning:
⓵ A properly balanced chemical equation means that the quantity of atoms on the reactants side matches that on the products side.
→ The equation lacks balance because there are 2 Nitrogen atoms and 2 Hydrogen atoms on the reactants side. In contrast, on the products side, there is only 1 Nitrogen atom and 4 Hydrogen atoms. Thus, the number of atoms on each side is not consistent!
Hopefully, this clarification is helpful; feel free to reach out if you have any further questions! ☻
