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liberstina
2 months ago
9

A syringe contains 0.65 moles of he gas that occupy 900.0 ml. what volume (in l) of gas will the syringe hold if 0.35 moles of n

e is added?
Chemistry
2 answers:
Tems11 [2.7K]2 months ago
8 0

The information provided indicates that:

  • Initial moles of gas n1 = 0.65 mol
  • The volume it occupies V1 = 900.0 ml
  • Moles of Neon added = 0.35 ml

Additional Explanation

To approach this problem, it's essential to reference Avogadro’s law, stating that "equal volumes of gases at the same temperature and pressure contain an equal number of molecules”.

Thus, we need to find the total moles of the gases.

(0.65 + 0.35) mol

1.00 mol

We also need to identify the volume V2 = unknown.

According to Avogadro’s law, the corresponding equation will be

0.65 mol x 900.0ml = 1.00ml x V2

585ml = 1.00 ml x v2

V2 = 585ml

Should we convert 585 ml to liters, we need to divide by 1000:

Thus, we have:

\frac{ 585ml}{1000}

0.6L

Consequently, the volume of gas in liters that the syringe can accommodate with the addition of 0.35 moles of neon is 0.6L.

LEARN MORE:

  • A syringe contains 0.65 moles of he gas that occupy 900.0 ml. what volume (in l) of gas will the syringe hold if 0.35 moles of ne is added?
  • A syringe contains 0.65 moles of he gas that occupy 750.0 ml.

KEYWORDS:

  • moles
  • syringe
  • convert
  • litres
  • avogradro's law
lions [2.9K]2 months ago
5 0
<span>Using PV=nRT, which represents a universal constant for any state, we have: P1V1/n1T1=R and P2V2/n2T2=R; This implies that: P1V1/n1T1=P2V2/n2T2 Thus we can express it as V1/n1=V2/n2. Rearranging yields: V2=V1 x (n2/n1) = 750 mL x ((0.65+0.35)/(0.65)) = 1200 mL = 1.2 L... with 2 significant figures</span>
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