What is the name for molecular compound N4O8?

The true statement is B. With identical masses for both metals, the final temperature of the two will be more aligned with 498 K rather than 298 K, as iron's specific heat capacity is significantly greater than that of gold's.

Explanation:

The rate at which gases effuse is inversely related to the square root of their molar masses.

In this case, half of the helium (1.5 L) passed through the membrane in 24 hours. Therefore, we can calculate the effusion rate of He gas as follows.

         

            = 0.0625 L/hr

Given that the molar mass of He is 4 g/mol and for it is 32 g/mol.

Now,

   

                               = 2.83

Thus, the effusion rate of

                       =

          Rate of = 0.022 L/hr.

This implies that 0.022 L of gas will effuse in one hour.

Consequently, to find the duration needed for 1.5 L of gas to effuse, we calculate as follows.

         

                = 68.18 hours

Thus, we can conclude that it will require 68.18 hours for half of the oxygen to effuse through the membrane.

M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL

From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.

Utilize the ideal gas law:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
Convert kPa to atm, where 1 Pa = 9.8 x 10^{-6} atm.
T = 293 K
V = 6.8 L
R = 1/12
Substituting all values leads to:
n = 0.272