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zysi
6 days ago
11

A friend climbs an apple tree and drops a 0.22-kg apple from rest to you, standing 3.5 m below. When you catch the apple, you br

ing it to rest in 0.28 s.
A.) What was the speed of the apple just before you caught it?

B.) What average force did you exert on the apple to bring it to rest? (Be sure to include both the weight of the apple and the force needed to bring it to rest.)

Physics
1 answer:
Keith_Richards [2.2K]6 days ago
3 0
(A) velocity = 2.8 m/s (B) Average force = 1.9536 Newtons.
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A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
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22 days ago
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A permeability test was run on a compacted sample of dirty sandy gravel. The sample was 175 mm long and the diameter of the mold
Maru [2360]

Answer:

(a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

Explanation:

Given that,

Length = 175 mm

Diameter = 175 mm

Time = 90 sec

Volume= 405 cm³

We need to calculate the discharge

Using formula of discharge

Q=\dfrac{V}{t}

Insert the values into the formula

Q=\dfrac{405}{90}

Q=4.5\ cm^3/s

(a). We will compute the coefficient of permeability

Applying the formula for permeability

Q=kiA

k=\dfrac{Q}{iA}

k=\dfrac{Ql}{Ah}

Where, Q=discharge

l = length

A = cross-sectional area

h=constant head that causes flow

Plugging the value into the formula

k=\dfrac{4.5\times175\times10^{-1}}{\dfrac{\pi(175\times10^{-1})^2}{4}\times38}

k=8.6\times10^{-3}\ cm/s

The coefficient of permeability measures as 8.6\times10^{-3}\ cm/s.

(c). To ascertain the discharge velocity during the testing phase

Utilizing the discharge velocity formula

v=ki

v=\dfrac{kh}{l}

Substituting the values into the equation

v=\dfrac{8.6\times10^{-3}\times38}{17.5}

v=0.0187\ cm/s

The discharge velocity during the test measures 0.0187 cm/s.

Thus, (a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity computes at 0.0330 cm/s.

(c). The observed discharge velocity during the test equals 0.0187 cm/s.

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8 days ago
A vehicle ___________ occurs when the driver begins to back up and is unaware that a person is behind the vehicle.
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I'm unaware of the term accident?
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28 days ago
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Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.​
Keith_Richards [2263]

Answer: The result to the query is 0.25 ohms

Explanation:

R = u x/A.......1

where u represents the resistivity of the

rod, A is the cross-sectional area, and x denotes

the length of the rod.

Let R* represent the resistance across the adjacent sections of the rod.

Then, R* = u1/4.......2

By comparing equation 1 with equation 2, we find that

R* = 1/4

which equals 0.25 ohms.

3 0
19 days ago
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