Answer:
the lump descends
Explanation:
The full articulation of the query is
Upon fully submerging a 3 kg lump of material in a certain fluid, the fluid that would have occupied the space now filled by the lump weighs 2 kg. (a) When released, does the lump float up, sink, or remain steady
(a)
= Buoyant force acting upward on the lump
= mass of irregular lump = 3 kg
= mass of fluid displaced = 2 kg
The upward buoyant force on the lump is given by the weight of the displaced fluid, thus
the weight of the irregular lump of material is represented as
Given that the weight of the lump downward exceeds the upward buoyant force, the lump will indeed descend
Answer:
Explanation:
The equation used to determine the maximum height of the bowling pin during its trajectory is given by;
H = u²/2g
where u, the initial speed/velocity, equals 10m/s
g stands for gravitational acceleration = 9.81m/s²
Substituting in the values gives us
H = 10²/2(9.81)
H = 100/19.62
Consequently, the highest point of the bowling pin's center of mass is approximately 5.0m.
Response:
0.60 m/s
Details:
The average speed between times t = a and t = b can be expressed as:
v_avg = (x(b) − x(a)) / (b − a)
Given the function x(t) = 0.36t² − 1.20t, and considering the interval from 1.0 to 4.0:
v_avg = (x(4.0) − x(1.0)) / (4.0 − 1.0)
v_avg = [(0.36(4.0)² − 1.20(4.0)) − (0.36(1.0)² − 1.20(1.0))] / 3.0
v_avg = [(5.76 − 4.8) − (0.36 − 1.20)] / 3.0
v_avg = [0.96 − (-0.84)] / 3.0
v_avg = 0.60
The average speed calculated is 0.60 m/s.
