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ozzi
26 days ago
9

A pot of water is heated over a fire, and then frozen peas are added to the hot water. What happens to the energy in this situat

ion?
The energy gained by the peas is lost by the water.
The peas lose energy as they are heated in the water.
Energy is transferred from the peas to the water and the pot.
The water receives energy both from the fire and from the frozen peas.
Energy is transferred from the fire to the pot, then to the water, and then to the peas.
Chemistry
2 answers:
alisha [2.9K]26 days ago
6 0
The answer is (d). When water is heated, its molecules absorb kinetic energy. Frozen peas contain potential energy, which is transferred to them from the hot water when they are added. Thus, the peas' molecules also gain kinetic energy. Hence, energy is passed from the fire to the pot, then to the water, and finally to the peas.
lions [2.9K]26 days ago
5 0
The correct answer is the fifth option. Energy transfers from the fire to the pot, subsequently to the water, and then to the peas.
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A) How many moles of CO2 and H2O are formed from 3.85 mole of propane C3H8 (This calculation needs to be done twice-once fro CO2
castortr0y [3046]

Answer:

11.55 moles of CO2 gas result from 3.85 moles of propane.

15.4 moles of H2O result from 3.85 moles of propane.

b) 0.5176 moles of water result from 0.647 moles of oxygen gas.

0.1294 moles of propane are reacted.

Explanation:

C_3H_7+5O_2\rightarrow 3CO_2+4H_2O

a) Amount of propane = 3.85 moles

The reaction indicates that for every mole of propane, 3 moles of carbon dioxide are produced.

Thus, 3.85 moles of propane yield:

\frac{3}{1}\times 3.85 mol=11.55 mol of carbon dioxide.

11.55 moles of CO2 gas result from 3.85 moles of propane.

The reaction also specifies that 1 mole of propane produces 4 moles of water.

Therefore, 3.85 moles of propane will generate:

\frac{4}{1}\times 3.85 mol=15.4 mol of water.

15.4 moles of H2O result from 3.85 moles of propane.

b) Amount of oxygen gas = 0.647 moles

The reaction states that 5 moles of oxygen yield 4 moles of water.

As a result, 0.647 moles of oxygen will produce:

\frac{4}{5}\times 0.647 mol=0.5176 mol of water.

0.5176 moles of water result from 0.647 moles of oxygen gas.

The reaction indicates that 5 moles of oxygen gas interact with 1 mole of propane.

Then, 0.647 moles of oxygen will cause:

\frac{1}{5}\times 0.647 mol=0.1294 mol of propane to react.

0.1294 moles of propane are reacted.

5 0
1 month ago
Find the specific heat of sikver in J/g C if 38.5 cal is required to heat 25.0g of silver from 31.5 C to 58.7 C (1cal=4.184 J)
alisha [2963]

Answer:

The specific heat value for silver is 0.236 J/g-C.

Explanation:

Silver has a mass of 25 grams.

The temperature shifts from 31.5° C to 58.7° C.

The required heat is equivalent to 25 g.

To determine silver's specific heat, the following equation applies:

Q=mc\Delta T

Where c represents the specific heat of silver.

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{38.5 \times 4.184}{25(58.7-31.5)}\\\\c=0.236\ J/g-C

Thus, the specific heat of silver is 0.236 J/g-C.

7 0
1 month ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
eduard [2782]

Answer:- 64015 J

Solution: The calorimeter contains 4250 mL of water, which is at a temperature of 22.55 degrees Celsius.

The water's density is 1 gram per mL.

Thus, the mass of water = 4250mL(\frac{1g}{1mL}) = 4250 grams.

After introducing the hot copper bar, the final temperature of the water reaches 26.15 degrees Celsius.

Thus, \Delta T for the water = 26.15 - 22.55 = 3.60 degrees Celsius.

The specific heat capacity of water is 4.184 \frac{J}{g.^0C}.

To determine the heat absorbed by the water, we can use the following formula:

q=mc\Delta T

where q represents heat energy, m refers to mass, and c indicates specific heat.

Now let's substitute the values into the equation to perform the calculations:

q=4250g*\frac{4.184J}{g.^0C}*3.60^0C

q = 64015 J

Therefore, the water absorbs 64015 J of heat.



5 0
1 month ago
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
Tems11 [2777]
The work done is 19.26 kJ.
5 0
9 days ago
If the kinetic energy of a particle is equal to twice its rest mass, what is the velocity of the particle? Determine if relativi
lorasvet [2795]

Answer:

The particle's velocity is calculated to be 2 m/s,

Explanation:

Kinetic energy refers to the energy an object possesses due to its movement. The formula for kinetic energy is:

K.E=\frac{1}{2}mv^2

Where:

m = the mass of the object

v = the object's velocity

A particle with mass m has a kinetic energy that is double its mass.

K.E=2m

2m=\frac{1}{2}mv^2

v^2=\frac{4}{1}

v=2

Since the velocity is measured in m/s, we determine that the particle's speed is 2 m/s.

8 0
1 month ago
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