Answer:
The pen requires 7.2 mJ of energy to extend.
Explanation:
Provided:
Length = 1.8 cm
Spring constant = 300 N/m
Initial compression = 1.0 mm
Additional compression = 6.0 mm
Total compression = 1.0 + 6.0 = 7.0 mm
We need to determine the energy needed
This energy is equivalent to the variation in spring potential energy
Substitute the values into the formula
Therefore, a total of 7.2 mJ is needed to extend the pen.
Answer:
a) ∆x∆v = 5.78*10^-5
∆v = 1157.08 m/s
b) 4.32*10^{-11}
Explanation:
This problem can be addressed using Heisenberg's uncertainty principle, which is expressed as:
Where h represents Planck’s constant (6.62*10^-34 J s).
Assuming that the electron's mass remains the same, we proceed as follows:
Utilizing the electron's mass (9.61*10^-31 kg) and the uncertainty in position (50 nm), we can compute ∆x∆v and ∆v:
If we treat the electron like a classic particle, the time required to cross the channel is determined using the upper limit of the uncertainty in velocity:
Answer:
0.130
Explanation:
The coefficients of static friction recorded for each trial are listed as follows:
1. 0.053
2. 0.081
3. 0.118
4. 0.149
5. 0.180
6. 0.198
Adding these coefficients together results in: 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198
= 0.779
Consequently;
the mean coefficient of static friction =
=
= 0.12983
The mean coefficient of static friction is 0.130
Based on the kinematic formula:
We have the following known information:
Acceleration a = 2.55 m/s²
We want to determine x.
Rearranging the equation, we get:
Therefore, the object travels a distance of 93.2 meters.