Part a consider another special case in which the inclined plane is vertical (θ=π/2). in this case, for what value of m1 would t

<span>I think this could be right, however, it is not safe. Personally, I would not approve the scenario as it poses risks to both the crane operators and the company. In my view, the answer is NO because although the crane might technically perform the movement, it shouldn't happen</span>.

The answer is 10pi. I believe this will be helpful.

Heat supplied to the gas = Q = 743 Joules

Work applied to the gas = W = -743 Joules

Additional explanation

The Ideal Gas Law that should be remembered is:

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Now, let’s proceed with the problem!

Given:

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

Unknown:

Work done on the gas = W =?

Heat supplied to the gas = Q =?

Solution:

Step A:

An ideal gas expands isothermally:

Next, we will determine the work performed on the gas:

Step B:

By utilizing the methodology mentioned earlier:

Next, we will ascertain the work completed on the gas:

Ultimately, we can calculate the total work done and heat supplied as follows:

Learn more

• Minimum Coefficient of Static Friction:
• The Pressure In A Sealed Plastic Container:
• Effect of Earth’s Gravity on Objects:

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

The full question reads;

Jason is employed at a moving company. A wooden crate weighing 75 kg is positioned on the wooden ramp of his truck, inclined at an angle of 11°.

What is the force magnitude, directed parallel to the ramp, that he needs to apply to initiate the upward movement of the crate?

Answer:

F = 501.5 N

Explanation:

We have the following information;

Mass of the wooden crate; m = 75 kg

Incline angle; θ = 11°

To move the wooden crate up, we must consider that friction is acting in the opposite direction of the movement along the inclined surface. Therefore, the force required can be expressed by;

F = mgsin θ + μmg cos θ

Using online resources, the coefficient of friction between wooden surfaces is μ = 0.5

Thus;

F = (75 × 9.81 × sin 11) + (0.5 × 75 × 9.81 × cos 11)

F = 501.5 N

Answer:

Explanation:

The data indicates that point A is located midway between two charges.

To calculate the electric field at point A, we begin with the field produced by charge -Q ( 6e⁻ ) at A:

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

This field points towards Q⁻.

A similar field will arise from the charge Q⁺, but it will direct away from Q⁺ toward Q⁻.

To find the resultant field, we add these contributions:

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

For the force acting on an electron placed at A:

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N