Burl the painter weighs 600 Newtons. He stands in the exact middle of his stage. There are two scale readings attached to the tw

o cords holding up the stage.
The image shows a painter standing in the middle of a scaffold that is hanging with two ropes on each end. Each rope has a spring scale.

What is the weight measured by each scale?

200 N
300 N
600 N
1200 N

Physics

You might be interested in

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

Yuliya22 [3333]

Answer:

$v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s$

Explanation:

In this scenario, we determine the initial velocity as follows:

$v_i = 7 \frac{m}{s}$

The final velocity in this instance can be expressed as:

$v_f = 13 \frac{m}{s}$

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

$v_f = v_i +at$

Solved for acceleration, we find:

$a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}$

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

$v_f = v_ i +a t$

Substituting into the equation yields:

$v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s$

5 0

4 months ago

A book that weighs 0.35 kilograms is kept on a shelf that’s 2.0 meters above the ground. A picture frame that weighs 0.5 kilogra

Softa [3030]

Upon calculating, I'm nearly certain that the answer is "...to a height of 1.4 meters." Happy to assist!:)

4 0

3 months ago

Read 2 more answers

Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl

serg [3582]

Answer:

b) TA = TB = TC

Explanation:

When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
The equilibrium state will be established once this equation is satisfied:

$\Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )$

Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

$(400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC$

At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
Therefore, option b) is correct.

8 0

3 months ago