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3 days ago

When a hole is made in the side of a container holding water, water flows out and follows a parabolic trajectory, similar to an

object in projectile motion. If the container is dropped in free fall, the water flow:
a. goes out in a straight line
b. curves upward
c. curves downward, but not parabolic
d. stops
e. cannot be predicted because not enough information is given.

Physics

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The relatively high resistivity of dry skin, about 1×106Ω⋅m, can safely limit the flow of current into deeper tissues of the bod

ValentinkaMS [3465]

Answer:

The resistance of the skin is 98 kΩ

Explanation:

Given:

Resistivity $\rho = 1 \times 10^{6}$ Ωm

Thickness $t = 1.5 \times 10^{-3}$ m

Resistivity of the skin:

$R = \frac{\rho t}{A}$

With assumed radius for the worker's palm,

$r = 7 \times 10^{-2}$ m

Area of the worker's palm,

$A = \pi r^{2}$

$A = 3.14 \times 49 \times 10^{-4}$

$A = 1.53 \times 10^{-2}$ $m^{2}$

Thus the resistance of palm is,

$R = \frac{10^{6} \times 1.5 \times 10^{-3} }{1.53 \times 10^{-2} }$

$R = 98 \times 10^{3}$ Ω

Consequently, the resistance of the skin is 98 kΩ

3 0

2 months ago

The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be m/s2. The mass of 3 wa

Keith_Richards [3271]

Answer:

The force will rise in direct relation to the mass of the objects

Explanation:

The gravitational acceleration remains constant. It is measured in meters per second squared or m/s². The average value is 9.81 m/s², calculated from observations made on varying surfaces. In reality, the acceleration can vary based on the geographical shape of the Earth relative to the earth's magnetic field and gravitational force.

For instance, if a single washer weighs 20 kg, with the gravity at 9.81 m/s², the weight would be:

F = ma

= $20 * 9.81\\= 196.2 N$

If there are three washers, the total weight calculates as:

F = 3 * 20 * 9.81

= 588.6 N

5 0

2 months ago

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A standard 14.16-inch (0.360-meter) computer monitor is 1024 pixels wide and 768 pixels tall. Each pixel is a square approximate

inna [3103]

Answer:

0.0031 m

Explanation:

y = Length of pixel = 281 μm

L = Distance to screen = 1.3 m

$\lambda$ = Wavelength = 550 nm

d = Pupil diameter

$\theta$ = Angle

We have the expression

$tan\theta=\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{281\times 10^{-6}}{1.3}$

We have the expression

$sin\theta=1.22\dfrac{\lambda}{d}\\\Rightarrow d=\dfrac{1.22\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1.22\times 550\times 10^{-9}}{sin\left(tan^{-1}\frac{281\times 10^{-6}}{1.3}\right)}\\\Rightarrow d=0.0031\ m$

The pupil diameter calculates to 0.0031 m

4 0

2 months ago

A 0.050-kg lump of clay moving horizontally at 12 m/s strikes and sticks to a stationary 0.15-kg cart that can move on a frictio

Ostrovityanka [3204]

Answer:

Explanation:

According to the parameters provided,

mass of the clay lump, m₁ = 0.05 kg

initial velocity of the lump, u₁ = 12 m/s

mass of the cart, m₂ = 0.15 kg

initial speed of the cart, u₂ = 0

As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:

$m_1u_1+m_2u_2=(m_1+m_2)v$

$v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$v=\dfrac{0.05\ kg\times 12\ m/s+0}{0.05\ kg+0.15\ kg}$

The resultant speed is v = 3 m/s.

Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.

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3 months ago

Water is made of two hydrogen atoms and one oxygen atom bonded together. Julia is describing how water undergoes a physical chan

kicyunya [3294]

Steam transforms into gas as it escapes into the atmosphere. Even if you manage to capture the steam as it ascends, it can revert to H2O when it cools down. Due to the evaporation process, the final volume of water will differ from the original amount.

8 0

3 months ago

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