A light wave has a 670 nm wavelength in air. Its wavelength in a transparent solid is 420 nm.

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A standard 14.16-inch (0.360-meter) computer monitor is 1024 pixels wide and 768 pixels tall. Each pixel is a square approximate

inna [3103]

Answer:

0.0031 m

Explanation:

y = Length of pixel = 281 μm

L = Distance to screen = 1.3 m

$\lambda$ = Wavelength = 550 nm

d = Pupil diameter

$\theta$ = Angle

We have the expression

$tan\theta=\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{281\times 10^{-6}}{1.3}$

We have the expression

$sin\theta=1.22\dfrac{\lambda}{d}\\\Rightarrow d=\dfrac{1.22\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1.22\times 550\times 10^{-9}}{sin\left(tan^{-1}\frac{281\times 10^{-6}}{1.3}\right)}\\\Rightarrow d=0.0031\ m$

The pupil diameter calculates to 0.0031 m

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A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist

Maru [3345]

a) x_{cm} = m₂/ (m₁ + m₂) d, b) x_{cm} = 52.97 pm

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