To find the temperature at which the volume of the gas would be 0.550 L, given that it is 0.432 L at -20.0 °C, apply Charles’s Law.
The formula is v1/T1 = v2/T2
Known values:
V1 = 0.550 L
T1 = ?
T2 = -20°C + 273 = 253 K
V2 = 0.432 L
Rearranging for T1:
T1 = (V1 × T2) / V2
Calculating:
T1 = (0.55 L × 253) / 0.432 L = 322.11 K or 49.11°C
The chemical equation can be expressed as:
2H2 + O2 = 2H2O
Given the amounts of the reactants, we need to identify the limiting reactant before calculating the amount of product generated.
4.0 g H2 ( 1 mol / 2.02 g ) = 1.98 mol H2
5.0 g O2 ( 1 mol / 32 g ) = 0.1563 mol O2
The limiting reactant is O2, as it will be fully consumed in the reaction.
0.1563 mol O2 ( 2 mol H2O / 1 mol O2 ) ( 18.02 g / mol ) = 5.6 g H2O will be produced
Answer:
The molar mass of the gas is 36.25 g/mol.
Explanation:
- To determine this, we utilize the mathematical relationship:
ν = 
Where, ν represents the speed of light in a gas (ν = 449 m/s),
R denotes the universal gas constant (R = 8.314 J/mol.K),
T stands for the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),
M is the molar mass of the gas in (Kg/mol).
ν = 
(449 m/s) = √(3(8.314 J/mol.K)(293 K)/M,
by squaring both sides:
(449 m/s)² = (3(8.314 J/mol.K)(293 K))/M,
thus M = (3(8.314 J/mol.K)(293 K)/(449 m/s)² = 7308.006/201601 = 0.03625 Kg/mol.
Thus, the molar mass of the gas is 36.25 g/mol.