Ask question

Ask question

All categories

3 months ago

15

The electron beam inside a television picture tube is 0.40 {\rm mm} in diameter and carries a current of 50 {\rm \mu A}. This el

ectron beam impinges on the inside of the picture tube screen.
How many electrons strike the screen each second?
The electrons move with a velocity of 4.0\times10^7\;{\rm m/s}. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 {\rm mm}?
Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the power delivered to the screen by the electron beam? (Hint: What potential difference produced the field that accelerated electrons? This is an emf.)

1 answer:

Yuliya22 [3.3K]3 months ago

8 0

Response:

A.3.13x10^14 electrons

B.330A/m²

C.9.11x10^5N/C

D. 0.23W

.Please review the attached document for further explanations

You might be interested in

What happens when you decrease the thrust on your scooter? A. You stop B. Nothing happens C. You fall over D. You speed up Reset

Yuliya22 [3333]

Response:

D. You accelerate

Clarification:

Hope this is helpful

4 0

2 months ago

To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th

Softa [3030]

Answer:

$H = 10.05 m$

Explanation:

The stone reaches the top of the flagpole at both t = 0.5 s and t = 4.1 s

therefore, the total duration of the upwards motion above the peak of the pole is provided as

$\Delta t = 4.1 - 0.5 = 3.6 s$

now we have

$\Delta t = \frac{2v}{g}$

$3.6 = \frac{2v}{9.8}$

$v = 17.64 m/s$

this indicates the speed at the flagpole's top

at this point we have

$v_f - v_i = at$

$17.64 - v_i = (-9.8)(0.5)$

$v_i = 22.5 m/s$

the height of the flagpole is stated as

$H = \frac{v_f + v_i}{2}t$

$H = \frac{22.5 + 17.64}{2} (0.5)$

$H = 10.05 m$

5 0

4 months ago

A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before

Ostrovityanka [3204]

Answer:

Explanation:

Provided:

mass of the steel ball $m=0.2\ kg$

initial velocity of the ball $u=10\ m/s$

Final velocity of the ball $v=-10\ m/s$ (moving upwards)

The impulse given is determined by the change in the momentum of the object.

<ptherefore the="" impulse="" j="" is="" defined="" by="">

$J=\Delta P$

$\Delta P=m(v-u)$

$\Delta P=0.2(-10-10)$

$\Delta =-4\ N-s$

Thus, the magnitude of the Impulse is 4 N-s.

</ptherefore>

7 0

3 months ago

Read 2 more answers

In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t

Keith_Richards [3271]

Answer:

$E_t_o_t_a_l=7.603MJ$

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, $W$ , is linked to its specific mechanical power. $Mechanical \ power$ calculated per unit mass can be derived from the following equation:

$\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ$

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

6 0

3 months ago