The quantity of fluorine in moles is calculated as 71/19 = 3.74
We also know that at standard temperature and pressure (273 K and 101.3 kPa), one mole of gas occupies 22.4 liters
So, the volume for 3.74 moles at S.T.P is: 3.74 x 22.4
This results in a volume of 83.776 L, which is equivalent to 83,776 mL
Next, applying Boyle's law, which states that for a fixed amount of gas,
PV = constant
We set up the equation P x 6843 = 101.3 x 83776
Solving for P gives us 1,240 kPa
The gravimetric factor for Ag2O within AgS amounts to 0.1078.
The proportion of component A by mass for substance AB is given by 75%.
Further explanation
According to Proust's Comparative Law, compounds are made from elements that maintain the same Mass Comparison, ensuring that compounds have a consistent ratio of elements.
The empirical formula presents the mole ratio of elements forming a compound.
In the case of substance AB₂, 60.0% of its mass is attributed to A.
For instance, if the mass of AB₂ is 100 grams, then the mass of A would be 60 grams, and the mass of B would be 40 grams, divided according to the coefficient in compound AB₂ which is 2, leading to 20 grams.
Thus, for compound AB, the total mass is the sum of mass A and mass B, which equals 60 grams plus 20 grams, resulting in a total mass of 80 grams.
Consequently, the percentage of compound A calculates to (60: 80) = 75%.
