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AURORKA
2 months ago
3

A student has a 10.0g sample of CaBr2 . Show the setup of the calculation to determine the number of moles of CaBr2 in the sampl

e. Include units in the setup.
Chemistry
1 answer:
eduard [2.7K]2 months ago
3 0

The number of moles of CaBr2 in the provided sample is 0.30127 moles

Explanation:

Provided data,

CaBr2 weight = 10 g

We determine,

Molar mass of CaBr2 = 199.886 g/mol

1 mole = 6.022×10^23

Mole = 10.00 g * 6.022×10^23 / 199.886 g/mol

Mole = 0.30127 moles

The number of moles of CaBr2 in the provided sample is 0.30127 moles

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Draw a lewis structure for hccl3. Show all unshared pairs and the formal charges
eduard [2782]

Explanation:

Lewis-dot structure: It illustrates how the atoms in a molecule are bonded together and indicates the presence of unpaired electrons in the molecule.

The molecule in question is, HCCl_3

Carbon possesses '4' valence electrons, hydrogen has '1' valence electron, and chlorine contains '7' valence electrons.

Consequently, the cumulative count of valence electrons in HCCl_3 = 1(1) + 1(4) + 3(7) = 26

Based on the electron-dot structure, there are 8 bonding electrons and 18 non-bonding electrons.

The electron-dot representation for HCCl_3 is depicted below.

Next, we need to assess the formal charges on carbon, hydrogen, and chlorine.

The formula for calculating formal charge:

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on carbon}=4-0-\frac{8}{2}=0

\text{Formal charge on hydrogen}=1-0-\frac{2}{2}=0

\text{Formal charge on chlorine}=7-0-\frac{2}{2}=0

6 0
29 days ago
A balloon contains 0.950 mol of nitrogen gas and has a volume of 25.5 L. How many grams of N2 should be released from the balloo
lorasvet [2795]

Answer:

Mass released = 8.6 g

Explanation:

Provided information:

Starting moles of nitrogen= 0.950 mol

Starting volume = 25.5 L

Final nitrogen mass released = ?

Final volume = 17.3 L

Calculation:

Equation:

V₁/n₁ = V₂/n₂

25.5 L / 0.950 mol = 17.3 L/n₂

n₂ = 17.3 L× 0.950 mol/25.5 L

n₂ = 16.435 L.mol /25.5 L

n₂ = 0.644 mol

Starting mass of nitrogen:

Mass = moles × molar mass

Mass = 0.950 mol × 28 g/mol

Mass = 26.6 g

Ending mass of nitrogen:

Mass = moles × molar mass

Mass = 0.644 mol × 28 g/mol

Mass = 18.0 g

Mass released = initial mass - ending mass

Mass released = 26.6 g - 18.0 g

Mass released = 8.6 g

6 0
2 months ago
Explain why CaCl2 is likely to have properties similar to those of CaBr2
Alekssandra [3086]

Answer:

Both CaCl2 and CaBr2 consist of elements (bromine and chlorine) from the same group (group 7).

Explanation:

In the periodic table, elements are arranged into groups based on their valence electron count in the outermost shell. Elements in the same group, which possess a similar number of valence electrons, typically exhibit similar chemical behaviors.

Chlorine and Bromine in CaCl2 and CaBr2 belong to group 7, known as HALOGENS, characterized by having 7 valence electrons in their outer shell.

The similarity in properties between CaCl2 and CaBr2 arises because both contain Chlorine and Bromine, leading to analogous reactions and behaviors when interacting with other compounds.

5 0
2 months ago
What is the molar mass of citric acid (C6H8O7) and baking soda (NaHCO3)?
Alekssandra [3086]

Answer:

1. 192.0 g/mol.

2. 84.0 g/mol.

Explanation:

  • The molar mass refers to the weight of all atoms combined in a molecule measured in grams per mole.
  • To find a molecule's molar mass, we begin by looking up the atomic weights of the relevant elements from the periodic table. Next, we tally the atoms present and multiply that by their respective atomic weights.

1. Molar mass of citric acid (C₆H₈O₇):

Molar mass of C₆H₈O₇ = 6(atomic mass of C) + 8(atomic mass of H) + 7(atomic mass of O) = 6(12.0 g/mol) + 8(1.0 g/mol) + 7(16.0 g/mol) = 192.0 g/mol.

2. Molar mass of baking soda (NaHCO₃):

Molar mass of NaHCO₃ = (atomic mass of Na) + (atomic mass of H) + (atomic mass of C) + 3(atomic mass of O) = (23.0 g/mol) + (1.0 g/mol) + (12.0 g/mol) + 3(16.0 g/mol) = 84.0 g/mol.

4 0
1 month ago
Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation
alisha [2963]

I believe this question has five choices available:

 

>an SN2 process has happened with reversal of configuration

>racemization followed by an S N 2 reaction

>an SN1 process has occurred resulting in reversal of configuration

>an SN1 reaction has taken place due to the formation of a carbocation

>an SN1 event followed by an S N 2 “backside” attack

 

 

 

The correct choice is:

an SN1 reaction has occurred due to carbocation formation 

4 0
1 month ago
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