Provided Information:
Length of inclined plane = 8 m
Height of inclined plane = 2 m
Weight of the ice block = 300 N
Required Information:
Force needed to push ice block = F =?
Answer:
Force needed to push the ice block = 75 N
Explanation:
The required force to push this ice block up an inclined plane is given by
F = Wsinθ
where W is the weight of the ice block and θ is the angle indicated in the attached image.
Using trigonometric ratios,
sinθ = opposite/hypotenuse
where the opposite side is the height of the inclined plane and the hypotenuse is the length of the inclined plane.
Thus, sinθ = 2/8
θ = sin⁻¹(2/8)
which leads to θ = 14.48°
Therefore, F = 300*sin(14.48)
results in F = 75 N
This indicates that a force of 75 N is necessary to push the ice block on the specified inclined plane.
