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Firdavs
2 months ago
7

1.- Un balín de acero a 20 C tiene un volumen de 0.004 m3. ¿Cuál es la dilatación que sufre cuando su temperatura aumenta a 50 C

?
Physics
1 answer:
Softa [3K]2 months ago
0 0

Answer:

\Delta V = 1.440\times 10^{-6}\,m^{3}

Explanation:

El cálculo del coeficiente de expansión volumétrica se realiza a partir de esta ecuación diferencial parcial (The calculation of the volumetric expansion coefficient is done using this partial differential equation):

\alpha = \frac{1}{V} \cdot \left(\frac{\partial V}{\partial T} \right)

La siguiente fórmula se integra (The subsequent formula is integrated):

\alpha\, dT = \frac{dV}{V}

Se asume que el coeficiente permanece constante (Assuming the coefficient remains constant):

\alpha \int\limits^{T_{f}}_{T_{o}}\,dT = \int\limits^{V_{f}}_{V_{o}}\, \frac{dV}{V}

\alpha \cdot (T_{f}-T_{o}) = \ln \frac{V_{f}}{V_{o}}

El volumen al final es (The final volume will be):

V_{f} = V_{o}\cdot e^{\alpha \cdot (T_{f}-T_{o})}

El coeficiente de expansión volumétrica para acero es 12\times 10^{-6}\,^{\circ}C^{-1} (The volumetric expansion coefficient for steel is 12\times 10^{-6}\,^{\circ}C^{-1}):

V_{f} = (0.004\,m^{3})\cdot e^{(12\times 10^{-6}\,^{\circ}C^{-1})\cdot (50^{\circ}C-20^{\circ}C)}

V_{f} \approx 4.001\times 10^{-3}\,m^{3}

Finalmente, la expansión que sufre el balín es (Finally, the expansion experienced by the pellet is):

\Delta V = 4.001\times 10^{-3}\,m^{3} - 4.000\times 10^{-3}\,m^{3}

\Delta V = 1.440\times 10^{-6}\,m^{3}

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A uniform bridge span weighs 50.0 x 10^3 N and is 40.0 m long. An automobile weighing 15.0 x 10^3 N is parked with its center of
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Explanation:

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Ultimately, substituting in the values provides the Left Force result:

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1 month ago
A transformer is to be designed to increase the 30 kV-rms output of a generator to the transmission-line voltage of 345 kV-rms.
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Answer:

n_s = 920 \turns

Explanation:

Given,

Voltage of the primary coil (V_p) = 30 kV-rms

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number of turns in the primary coil (n_p) = 80 turns

number of turns in the secondary coil (n_s) =?

the ratio of turns between primary and secondary coils

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     \dfrac{n_s}{n_p} = \dfrac{V_s}{V_p}

     n_s = n_p \dfrac{V_s}{V_p}

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     n_s = 920 \turns

The number of turns in the secondary coil is equal to n_s = 920 \turns

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