<span>First, apply Newton's second law of motion: F = ma.
Force equals mass times acceleration.
This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time,
we have force = (mass * velocity) / time,
leading us to conclude that (mass * velocity) / time will equal momentum / time.
Hence, we derive the equation mass * velocity = momentum.
Momentum = mass * velocity.
For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s,
Momentum = 6300 * 0.11,
resulting in P = 693 kg (m/s).
For the dolphin, having a mass of 50 kg and moving at 10.4 m/s,
Momentum = 50 * 10.4,
yielding P = 520 kg (m/s).
Thus, the elephant has a greater momentum (P) due to its larger size.</span>
Answer:
An examination is conducted to assess how basic thin airfoils perform in slightly supersonic flow conditions, utilizing the nonlinear transonic theory initially proposed by von Kármán[1]. Formulas for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are devised based on a transonic similarity variable. Aerodynamic coefficients are computed in similarity form for flat plates and asymmetric wedge airfoils, and their graphical representations are created. Sample plots are provided for a flat plate and a particular asymmetric wedge, shown on conventional coordinate axes of Cl, Cd, and Cmc/4 in relation to angle of attack and Cl against Mach Number to showcase distinct characteristics of nonlinear flow.
Explanation:
To tackle this question, we know the following:
1 Albert equals 88 meters.
1 A = 88 m.
Initially, we square both sides of the equation:
(1 A)^2 = (88 m)^2
1 A^2 = 7,744 m^2
<span>Since 1 acre equals 4,050 m^2, let’s divide both sides by 7,744 to find out how many acres match this value:</span>
1 A^2 / 7,744 = 7,744 m^2 / 7,744
(1 / 7,744) A^2 = 1 m^2
Then multiply both sides by 4,050.
(4050 / 7744) A^2 = 4050 m^2
0.523 A^2 = 4050 m^2
<span>Thus, one acre is approximately 0.52 square alberts.</span>
Even if we lack details about the size of the pressure cooker or the altitude of its operation, we can reliably assess the force on the lid based on prior knowledge because, similar to boiling water, the pressure buildup inside the cooker increases in line with the rising temperature.
