What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. gra

Question

3 months ago

12

ms of H2O(l)?

2 answers:

eduard [2.7K] · Answer 1 · 2026-02-25T22:38:14+03:00

The concentration of O₂ in H₂O can be expressed as ppm

ppm stands for parts per million - mg/kg

indicating the quantity of mg in 1 kg of solution

Here, the mass of O₂ is 0.008 g

Since 1000 mg equals 1 g

the mass of O₂ in mg is calculated as - 0.008 g x 1000 mg/g = 8 mg

The mass of the water amounts to 1000 g

which is the same as 1 kg

thus the mass of water in kg is - 1000 g / 1000 g/kg = 1 kg

therefore, there are 8 mg of O₂ in 1 kg of water

which gives a concentration of O₂ of - 8 mg/kg

this can also be represented as 8 ppm

the final answer is 8 ppm

Tems11 [2.7K] · Answer 2 · 2026-02-25T22:34:03+03:00

Answer: The concentration of $O2(g)$ in parts per million is 8 ppm

Solution: Provided information:

Mass of the solute (oxygen gas) = 0.008 g

Mass of the solvent (water) = 1000 g

The first step is to compute the overall mass of the solution.

Total mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Next, we must determine the concentration of $O2(g)$ in parts per million.

ppm is defined as the mass of solute in one million $(10^6)$ parts by mass of the solution.

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Now applying the values we have results in

$ppm=\frac{0.008g}{1000.008g}\times 10^6=7.99=8ppm$

Thus, the concentration of $O2(g)$ in ppm is 8 ppm