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hram777
7 days ago
10

We have two equal size boxes, A and B. Each box contains gas that behaves as an ideal gas. We insert a thermometer into each box

and find that the gas in box S is at a temperature of 50°C while that in B is at 10°C. This is all we know about the gas in the boxes. Which of the following statements MUST be true? Which COULD be true? Explain the reasoning behind your answers.
a) The pressure in A is higher than in B
b) There are more molecules in A than in B
c) A and B cannot contain the same type of gas
d) The molecules in A have more average kinetic energy per molecule than those in B
e) The molecules in A are moving faster than those in B
Physics
1 answer:
Yuliya22 [1.1K]7 days ago
5 0

Response:

d) In container A, the average kinetic energy per molecule exceeds that of container B.

e) Molecules in A exhibit a higher speed than those in B.

Reasoning:

Both containers are of identical size.

This indicates that the volume of each container is equal to V.

Temperature in container A is 50°C, which equals 323 K.

Temperature in container B is 10°C, equating to 283 K.

According to the ideal gas law:

P V = m R T

The quantities of gas mass are unspecified, making it impossible to determine which has a higher temperature or a greater number of molecules.

However, it is known that the average kinetic energy is directly related to the absolute temperature of a gas; thus, the kinetic energy in container A is greater due to its higher temperature. A higher kinetic energy implies increased molecular velocity.

Consequently, options d and e are accurate.

d) In container A, the average kinetic energy per molecule exceeds that of container B.

e) Molecules in A exhibit a higher speed than those in B.

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When 999mm is added to 100m ______ is the result​
Keith_Richards [1034]

Answer:

The outcome of adding 999mm to 100m is 101m.

Explanation:

That's my belief.

6 0
5 days ago
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Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
Yuliya22 [1153]

Answer:

Explanation:

a )

Each blade resembles a rod with its axis positioned near one end.

The moment of inertia for one blade is:

= 1/3 x m l²

where m stands for the mass of the blade

l represents the length of each blade.

Total moment of inertia for 3 blades is:

= 3 x\frac{1}{3}  x m l²

ml²

2 )

Details provided include:

m = 5500 kg

l = 45 m

Substituting these values produces:

moment of inertia of one blade:

= 1/3 x 5500 x 45 x 45

= 37.125 x 10⁵ kg.m²

Moment of inertia for 3 blades:

= 3 x 37.125 x 10⁵ kg.m²

= 111.375 x 10⁵ kg.m²

c )

Angular momentum

= I x ω

I denotes the moment of inertia of the turbine

ω symbolizes angular velocity

ω = 2π f

f indicates the rotational frequency of the blades

d )

We have I = 111.375 x 10⁵ kg.m² (Calculated)

f = 11 rpm (revolutions per minute)

= 11 / 60 revolutions per second

ω = 2π f

=  2π x  11 / 60 rad / s

Calculating angular momentum yields

= I x ω

111.375 x 10⁵ kg.m² x  2π x  11 / 60 rad / s

= 128.23 x 10⁵  kgm² s⁻¹.

4 0
2 days ago
Multiply the number 4.48E-8 by 5.2E-4 using Google. What is the correct answer in scientific notation?
Ostrovityanka [942]

Answer:

2.32\times 10^{-11}

Explanation:

The first number is 4.48\times 10^{-8}.

The second number is 5.2\times 10^{-4}.

We must multiply these two numbers together.

4.48\times 10^{-8}\times 5.2\times 10^{-4}=(4.48\times 5.2)\times 10^{(-8-4)}\\\\=23.296\times 10^{-12}

In scientific notation: 2.32\times 10^{-11}

Therefore, this is the solution you are looking for.

8 0
13 days ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Sav [1105]

Complete Question

An aluminum "12 gauge" wire measures a diameter of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field E in the wire varies over time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is recorded in seconds.

At time 5 seconds, I = 1.2 A.

We need to find the charge Q traveling through a cross-section of the conductor from time 0 to time 5 seconds.

Answer:

The charge is  Q =2.094 C

Explanation:

The question indicates that

    The wire’s diameter is  d = 0.205cm = 0.00205 \ m

     The radius of the wire is  r = \frac{0.00205}{2} = 0.001025 \ m

     Aluminum's resistivity is 2.75*10^{-8} \ ohm-meters.

       The electric field variation is described as

         E (t) = 0.0004t^2 - 0.0001 +0.0004

     

The charge is effectively given by the equation

       Q = \int\limits^{t}_{0} {\frac{A}{\rho} E(t) } \, dt

Where A is the area expressed as

       A = \pi r^2 = (3.142 * (0.001025^2)) = 3.30*10^{-6} \ m^2

 Thus,

       \frac{A}{\rho} = \frac{3.3 *10^{-6}}{2.75 *10^{-8}} = 120.03 \ m / \Omega

Therefore

      Q = 120 \int\limits^{t}_{0} { E(t) } \, dt

By substituting values

      Q = 120 \int\limits^{t}_{0} { [ 0.0004t^2 - 0.0001t +0.0004] } \, dt

     Q = 120 [ \frac{0.0004t^3 }{3} - \frac{0.0001 t^2}{2} +0.0004t] } \left | t} \atop {0}} \right.

The question states that t =  5 seconds

           Q = 120 [ \frac{0.0004t^3 }{3} - \frac{0.0001 t^2}{2} +0.0004t] } \left | 5} \atop {0}} \right.

          Q = 120 [ \frac{0.0004(5)^3 }{3} - \frac{0.0001 (5)^2}{2} +0.0004(5)] }

         Q =2.094 C

     

5 0
10 days ago
The air temperature over a lake decreases linearly with height after sunset, since air cools faster than water. The mean molar m
Yuliya22 [1153]

Answer: t = 0.878s

Explanation: A note for you,

since the temperature decreases in a straight line, you can expect the movement speed to also behave linearly. However, this isn't exactly true (referring to the formula). Alternatively, utilize the interpolation principle: (x/v_surface + x/v_top)/2 = t.

While the answer may not match exactly, it should be a close approximation. You can use this formula, thus avoiding large distance calculations.

7 0
14 days ago
Read 2 more answers
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