The force due to electricity on the charge is calculated by multiplying the charge by the intensity of the electric field:
in our scenario, where
and
, resulting in the force of
Initially, the kinetic energy of the particle is at zero (as it remains stationary), which means its final kinetic energy is equal to the work performed by the electric force over a distance of x=4 m:
The soccer ball's initial speed stands at 16.38 m/s. Given that the vertical distance is y = 2.44 m, the horizontal span x = 10.0 m, and the angle of launch θ = 25.0°. The initial velocity comprises two components, Vₓ and V. The calculations are as follows: Vₓ = V cosθ and V = V sinθ. The formula for horizontal distance becomes x = Vₓt. Since g is deemed 0, we can state that: x = Vₓt or 10 = V cos 25 * t. Solving for V gives us 10 = 0.906V * t, thus V * t = 10 / 0.906 = 11.038 m. Regarding the vertical distance (with g being negative due to the upward movement opposing gravity), we use y = V sinθ * t - 1/2 * g * t². Following through with the calculations leads us to determine that the soccer ball's initial speed is indeed 16.38 m/s.
Answer:
The total energy can be expressed as 
Explanation:
The problem states that
The Poynting vector, which measures energy flux, equals 
The rectangle's length is represented by 
The width of the rectangle is 
The duration considered is 
Mathematically, the overall electromagnetic energy incident on the area is given by
where A denotes the area of the rectangle, calculated as
By plugging in the respective values
Again substituting values
Answer:
θ = 61.3°
Alicia must swim at an angle of 61.3°
Explanation:
Parameters given include:
Width of the river = 100 m
Alicia's speed in still water = 2.5 m/s
Speed of river's current = 1.2 m/s
The angle she needs to swim can be determined by combining the velocities, taking into account the current's influence.
Her swimming speed aimed against the current must offset the current's velocity;
2.5cosθ - 1.2 = 0
2.5cosθ = 1.2
cosθ = 1.2/2.5
θ = cosinverse(1.2/2.5)
θ = 61.3°
Initially, the magnetic domains within the nail were oriented in various directions before coming into contact with the bar magnet. Upon Taylor touching the nail to the bar magnet, the magnetic fields of those domains became aligned, thus transforming the nail into a temporary magnet.
